Consider the molecule ethene (). How many sigma and pi bonds are present in this molecule?
A
sigma bonds and pi bonds
B
sigma bonds and pi bonds
C
sigma bonds and pi bond
D
sigma bonds and pi bonds
0 댓글
검증된 단계별 안내
1
Start by drawing the Lewis structure of ethene (C\_2H\_4). Ethene consists of two carbon atoms double bonded to each other, with each carbon atom bonded to two hydrogen atoms.
Recall that a single bond consists of one sigma (σ) bond, and a double bond consists of one sigma (σ) bond and one pi (π) bond.
Count the sigma bonds: Each C–H bond is a single bond, so each is one sigma bond. Since there are four C–H bonds, that gives 4 sigma bonds. The C=C double bond contains one sigma bond, so add 1 more sigma bond.
Count the pi bonds: The C=C double bond has one pi bond in addition to the sigma bond, so there is 1 pi bond in ethene.
Sum up the total bonds: Total sigma bonds = 4 (C–H) + 1 (C=C) = 5 sigma bonds; Total pi bonds = 1 (from the C=C double bond).