Determine the two major products (not including stereoisomers) when the following molecule undergoes free-radical bromination. [Note: Free-radical bromination is highly selective so only the most stable radical forms.]

Use the bond-dissociation energies from the given table to determine whether the bromination of propane would be selective or not.

What is radical selectivity in the context of radical halogenation reactions?

Why is fluorination considered non-selective and potentially explosive?

If radical halogenation occurs at a chiral center, what is the expected result in terms of stereochemistry?