For the following ¹H NMR spectrum and the given molecular formula, determine the plausible structure of the organic compound.

(Hint: There is a presence of C=O based on the IR spectrum of this compound that is not shown here.)

The spectrum information below is displayed as we see it in research journals. Draw the structure of the given data set.

C₆H₁₂O₂: ¹H NMR: δ 1.19 (6H, doublet), 1.21 (3H, triplet), 2.41 (2H, quartet), 4.93 (1H, septet); IR (cm^-1): 1750, 1210

When 2-chloro-2,3-dimethylbutane is treated with different strong bases then elimination causes the formation of two isomers (A and B) with formula C₆H₁₂. When sodium hydroxide is used as a base then the major product is isomer A and when tert-butoxide is used as a base then the isomer B is formed in a higher quantity.

a. Determine the structures of the two isomers using the NMR spectra given below.

b. Explain why isomer A predominates when sodium hydroxide is used while isomer B predominates when tert-butoxide is used.

How can the following compounds be distinguished using only the techniques listed below and no other information?
a. using proton NMR spectroscopy
b. using ¹³C NMR with DEPT experiments.
c. using Infrared spectroscopy

A compound has the molecular formula C6H10. What is its Index of Hydrogen Deficiency (IHD)?