Simplify the radical. 63 x 2 \sqrt{63x^2} 63 x 2 <path d="M95,702 c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5,-10,-9.5,-14 c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54 c44.2,-33.3,65.8,-50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10 s173,378,173,378c0.7,0,35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429 c69,-144,104.5,-217.7,106.5,-221 l0 -0 c5.3,-9.3,12,-14,20,-14 H400000v40H845.2724 s-225.272,467,-225.272,467s-235,486,-235,486c-2.7,4.7,-9,7,-19,7 c-6,0,-10,-1,-12,-3s-194,-422,-194,-422s-65,47,-65,47z M834 80h400000v40h-400000z">

Everyone, so let's take a look at this example problem here, a practice problem. So we've got the square root of 63x2. So remember what happens when we have numbers and variables inside of square roots or radicals? You can always just split them up and deal with them independently. So I can split this up so that I basically just have the square root of 63 and then times the square root of x squared, And if some of these things aren't perfectly simplified, just try to pull out perfect powers from them. Alright? So is 63 perfectly simplified? Well, no, because it's not a prime number. There's a few numbers that will multiply to that. So let's try to work on the 63 first. So can I pull out a 4 from a 63? 4 doesn't go into 63, so that doesn't work. What about a 9? So does 63 divided by 9? Well, this is where multiplication tables become handy. 9 times 7 is 63, so that means I can split this up into square root of 9 times square root of 7. And this is helpful because this basically just turns into 3 root 7, 3 square root 7. Alright? So that's the 63, that one's done. What about the x squared? Well, you'll notice here what I've got is I've got x that's squared, but then I'm square rooting it. So what happens when I square a number and then square root it? Basically, I'm just undoing it, and this really just pull you know, just just simplifies to x. So the square root of square the so x squared is a perfect square, and this just simplified sounds to 1 power of x. So basically, what happens here is I'm gonna drop this all the way down, and this is just multiplied by x. Now, usually, what you will see is you won't see something like 3 square root of 7 x because it looks a little weird because, so what one of the things that you'll see is that the x usually gets brought out in front of the radical. So this is gonna be 3x times the square root of 7, and that is the most simplified this thing could be. Alright. So that's it for this one, folks. Let me know if you have any questions.

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0. Fundamental Concepts of Algebra

Simplifying Radical Expressions

Precalculus

0. Fundamental Concepts of Algebra

Simplifying Radical Expressions

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객관식

Simplify the radical.
$\sqrt{63x^2}$

$63$\sqrt{x}$$

$3$\sqrt{7x}$$

$x$\sqrt{63}$$

$3x$\sqrt$7$

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Identify the expression under the square root: $ \sqrt{63x^2} $.

Break down the expression under the square root into its prime factors: $ 63x^2 = 9 \times 7 \times x^2 $.

Recognize that $ 9 $ is a perfect square and $ x^2 $ is also a perfect square. Therefore, $ \sqrt{9} = 3 $ and $ \sqrt{x^2} = x $.

Simplify the square root by taking the square root of the perfect squares: $ \sqrt{63x^2} = \sqrt{9} \times \sqrt{7} \times \sqrt{x^2} = 3x\sqrt{7} $.

The simplified form of the radical expression is $ 3x\sqrt{7} $.