Understand that the expression \( \sin^{-1}\left(\frac{\sqrt{2}}{2}\right) \) asks for the angle whose sine is \( \frac{\sqrt{2}}{2} \).
Recall that the sine of \( \frac{\pi}{4} \) is \( \frac{\sqrt{2}}{2} \). Therefore, \( \sin^{-1}\left(\frac{\sqrt{2}}{2}\right) = \frac{\pi}{4} \).
Consider the range of the inverse sine function, which is \([-\frac{\pi}{2}, \frac{\pi}{2}]\). This means the principal value of \( \sin^{-1} \) will be within this interval.
Verify that \( \frac{\pi}{4} \) is within the range of \([-\frac{\pi}{2}, \frac{\pi}{2}]\), confirming it as a valid solution.
Conclude that the correct angle corresponding to \( \sin^{-1}\left(\frac{\sqrt{2}}{2}\right) \) is \( \frac{\pi}{4} \).