Write the single logarithm as a sum or difference of logs. log5(x35(2x+3)2)
A
5+2log5(2x+3)−log53x
B
2log5(2x+3)−3log5x
C
1+2log5(2x+3)−3log5x
D
log5(2x+3)−log5x
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1
Start by applying the properties of logarithms to the given expression: \( \log_5 \left( \frac{5(2x+3)^2}{x^3} \right) \).
Use the quotient rule for logarithms: \( \log_b \left( \frac{M}{N} \right) = \log_b M - \log_b N \). This gives us \( \log_5(5(2x+3)^2) - \log_5(x^3) \).
Apply the product rule for logarithms: \( \log_b(MN) = \log_b M + \log_b N \). This results in \( \log_5 5 + \log_5 (2x+3)^2 \).
Use the power rule for logarithms: \( \log_b(M^n) = n \log_b M \). This transforms \( \log_5 (2x+3)^2 \) into \( 2 \log_5 (2x+3) \).
Combine all the terms: \( \log_5 5 + 2 \log_5 (2x+3) - 3 \log_5 x \). Simplify \( \log_5 5 \) to 1, resulting in \( 1 + 2 \log_5 (2x+3) - 3 \log_5 x \).