A health clinic is studying the effectiveness of a new flu vaccine. In a random sample of 80 patients who received the vaccine, 68 did not get the flu during the season. Make a 99% confidence interval for the true proportion of vaccinated individuals who are protected from the flu. We are ___% confident that between (––––,––––) of vaccinated individuals are protected from the flu.
A
,
B
,
C
,
D
,
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Step 1: Identify the sample proportion (p̂). The sample proportion is calculated as the number of successes (patients who did not get the flu) divided by the total sample size. Use the formula: p̂ = x / n, where x = 68 and n = 80.
Step 2: Calculate the standard error (SE) for the sample proportion. The formula for the standard error is: SE = sqrt((p̂ * (1 - p̂)) / n). Substitute the value of p̂ from Step 1 and n = 80 into this formula.
Step 3: Determine the critical value (z*) for a 99% confidence level. For a 99% confidence interval, the critical value corresponds to the z-score that leaves 0.5% in each tail of the standard normal distribution. This value can be found in a z-table or using statistical software.
Step 4: Compute the margin of error (ME). The margin of error is calculated using the formula: ME = z* * SE. Substitute the values of z* from Step 3 and SE from Step 2 into this formula.
Step 5: Construct the confidence interval. The confidence interval is given by: (p̂ - ME, p̂ + ME). Substitute the values of p̂ from Step 1 and ME from Step 4 to find the lower and upper bounds of the interval.