What type of variable is required to construct a confidence interval for a population proportion?
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8. Sampling Distributions & Confidence Intervals: Proportion
Confidence Intervals for Population Proportion
객관식
Over the first days of the semester, one student is late to class on days. Construct a confidence interval for the true proportion of time this student is late.
A
(0.276, 0.324)
B
(0.131, 0.469)
C
(0.3, 0.7)
D
(0.062,0.538)
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검증된 단계별 안내1
Identify the sample proportion (p̂) by dividing the number of days the student was late (66) by the total number of days (2020). This gives p̂ = 66/2020.
Determine the standard error (SE) of the sample proportion using the formula: SE = sqrt((p̂ * (1 - p̂)) / n), where n is the sample size (2020).
Find the critical value (z*) for a 98% confidence interval. This value corresponds to the z-score that captures the central 98% of the standard normal distribution. You can find this value using a z-table or statistical software.
Calculate the margin of error (ME) by multiplying the critical value (z*) by the standard error (SE): ME = z* * SE.
Construct the confidence interval by adding and subtracting the margin of error from the sample proportion: (p̂ - ME, p̂ + ME). This interval estimates the true proportion of time the student is late with 98% confidence.
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