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Ch. 7 - Estimating Parameters and Determining Sample Sizes
Triola - Elementary Statistics 14th Edition
Triola14th EditionElementary StatisticsISBN: 9780137366446당신이 사용하는 게 아니라요?교과서 변경
7장, 문제 7.2.34b

Finite Population Correction Factor If a simple random sample of size n is selected without replacement from a finite population of size (n>0.05N), and the sample size is more than 5% of the population size , better results can be obtained by using the finite population correction factor, which involves multiplying the margin of error E by [Image]. Refer to the weights of the M&M candies in Data Set 38 “Candies” in Appendix B.


b. Use only the red M&Ms and treat that sample as a simple random sample selected from the population of the 345 M&Ms listed in the data set. Find the 95% confidence interval estimate of the mean weight of all 345 M&Ms. Compare the result to the actual mean of the population of all 345 M&Ms.

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Step 1: Identify the given values and conditions. From the problem, the population size (N) is 345, and the sample size (n) is such that n > 0.05N, meaning the sample size is more than 5% of the population. This condition necessitates the use of the finite population correction factor.
Step 2: Recall the formula for the finite population correction factor (FPCF), which is: \( \sqrt{\frac{N - n}{N - 1}} \). Here, N is the population size, and n is the sample size. This factor will be used to adjust the margin of error.
Step 3: Calculate the margin of error (E) for the confidence interval. The formula for E is: \( E = z \cdot \frac{s}{\sqrt{n}} \), where z is the z-score corresponding to the 95% confidence level (typically 1.96), s is the sample standard deviation, and n is the sample size. Compute this value first without applying the correction factor.
Step 4: Adjust the margin of error using the finite population correction factor. Multiply the previously calculated margin of error (E) by the correction factor \( \sqrt{\frac{N - n}{N - 1}} \). This gives the corrected margin of error.
Step 5: Construct the 95% confidence interval for the mean weight of the M&Ms. The formula is: \( \text{Confidence Interval} = \bar{x} \pm E \), where \( \bar{x} \) is the sample mean and E is the corrected margin of error. Compare the resulting confidence interval to the actual mean of the population to evaluate the accuracy of the estimate.

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주요 개념

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Finite Population Correction Factor

The Finite Population Correction Factor (FPC) is used when sampling without replacement from a finite population. It adjusts the margin of error to account for the reduced variability in the sample when a significant portion of the population is sampled. Specifically, when the sample size exceeds 5% of the population, the FPC helps provide a more accurate estimate of the population parameters.
추천 영상:
04:48
Population Standard Deviation Known

Confidence Interval

A confidence interval is a range of values, derived from sample statistics, that is likely to contain the true population parameter with a specified level of confidence, typically 95%. It is calculated using the sample mean, the standard error, and a critical value from the normal distribution. This interval provides insight into the precision of the sample estimate and the uncertainty associated with it.
추천 영상:
06:33
Introduction to Confidence Intervals

Simple Random Sampling

Simple random sampling is a fundamental sampling technique where each member of the population has an equal chance of being selected. This method ensures that the sample is representative of the population, minimizing bias. In the context of the question, treating the selected red M&Ms as a simple random sample allows for valid statistical inferences about the mean weight of all M&Ms in the population.
추천 영상:
05:11
Sampling Distribution of Sample Proportion
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b. How does the result compare to the confidence interval found in Exercise 14 in Section 7-3?


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b. Assume that 22% of adults can wiggle their ears (based on data from Soul Publishing).

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b. Assume that 11% of consumers have a smartphone and plan to upgrade to a new model.


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b. Use the results from the 2014 survey.


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Voting Survey In a survey of 1002 people, 70% said that they voted in a recent presidential election (based on data from ICR Research Group). Voting records show that 61% of eligible voters actually did vote.


b. Find a 95% confidence interval estimate of the percentage of people who say that they voted.


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b. Given that Exercise 20 in Section 7-2 used the same data for a 99% confidence interval based on use of the t distribution, and given that the data do not appear to be from a normally distributed population, which confidence interval is likely to be better: The confidence interval from part (a) or the confidence interval found in Exercise 20 in Section 7-2?


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