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Ch. 1 - Angles and the Trigonometric Functions
1์žฅ, ๋ฌธ์ œ 1.2.72

If ฮธ is an acute angle and cos ฮธ = 1/3, find csc (๐œ‹/2 - ฮธ).

๊ฒ€์ฆ๋œ ๋‹จ๊ณ„๋ณ„ ์•ˆ๋‚ด
1
Recall the co-function identity for sine and cosine: \(\sin\left(\frac{\pi}{2} - \theta\right) = \cos\theta\).
Since \(\csc x = \frac{1}{\sin x}\), express \(\csc\left(\frac{\pi}{2} - \theta\right)\) as \(\frac{1}{\sin\left(\frac{\pi}{2} - \theta\right)}\).
Substitute the co-function identity into the expression: \(\csc\left(\frac{\pi}{2} - \theta\right) = \frac{1}{\cos\theta}\).
Use the given value \(\cos\theta = \frac{1}{3}\) to rewrite the expression as \(\csc\left(\frac{\pi}{2} - \theta\right) = \frac{1}{\frac{1}{3}}\).
Simplify the fraction to find the expression for \(\csc\left(\frac{\pi}{2} - \theta\right)\) in terms of the given cosine value.

๋น„์Šทํ•œ ๋ฌธ์ œ์— ๋Œ€ํ•œ ๊ฒ€์ฆ๋œ ์˜์ƒ ๋‹ต๋ณ€:

์ด ์˜์ƒ ํ•ด๋ฒ•์€ ์œ„ ๋ฌธ์ œ์— ๋„์›€์ด ๋œ๋‹ค๊ณ  ํŠœํ„ฐ๋“ค์ด ์ถ”์ฒœํ•œ ๊ฒƒ์ž…๋‹ˆ๋‹ค.
์˜์ƒ ๊ธธ์ด:
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๋„์›€์ด ๋˜์—ˆ๋‚˜์š”?

์ฃผ์š” ๊ฐœ๋…

์งˆ๋ฌธ์— ์˜ฌ๋ฐ”๋ฅด๊ฒŒ ๋‹ตํ•˜๊ธฐ ์œ„ํ•ด ๋ฐ˜๋“œ์‹œ ์ดํ•ดํ•ด์•ผ ํ•˜๋Š” ํ•ต์‹ฌ ๊ฐœ๋…๋“ค์€ ๋‹ค์Œ๊ณผ ๊ฐ™์Šต๋‹ˆ๋‹ค.

Complementary Angles in Trigonometry

Complementary angles are two angles whose measures add up to 90ยฐ (or ฯ€/2 radians). In trigonometry, the sine of an angle equals the cosine of its complement, i.e., sin(ฯ€/2 - ฮธ) = cos ฮธ. This relationship helps simplify expressions involving complementary angles.
์ถ”์ฒœ ์˜์ƒ:
3:35
Intro to Complementary & Supplementary Angles

Reciprocal Trigonometric Functions

Reciprocal functions are the inverses of the basic trigonometric functions. For example, cosecant (csc) is the reciprocal of sine, defined as csc ฮธ = 1/sin ฮธ. Understanding this helps in converting between sine and cosecant values to solve problems.
์ถ”์ฒœ ์˜์ƒ:
6:04
Introduction to Trigonometric Functions

Using Given Values to Find Trigonometric Ratios

Given a trigonometric value like cos ฮธ = 1/3, you can find related ratios using identities. Since sin(ฯ€/2 - ฮธ) = cos ฮธ, knowing cos ฮธ allows direct calculation of sin(ฯ€/2 - ฮธ), and thus csc(ฯ€/2 - ฮธ) by taking the reciprocal. This approach simplifies problem-solving.
์ถ”์ฒœ ์˜์ƒ:
04:42
Solve Trig Equations Using Identity Substitutions