Determine the amplitude, period, and phase shift of each function. Then graph one period of the function.
y = 1/2 sin(x + π)

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Identify the general form of the sine function: \(y = A \sin(B(x - C))\), where \(A\) is the amplitude, \(\frac{2\pi}{B}\) is the period, and \(C\) is the phase shift.

Rewrite the given function \(y = \frac{1}{2} \sin(x + \pi)\) in the form \(y = A \sin(B(x - C))\). Notice that \(x + \pi\) can be written as \(x - (-\pi)\), so here \(A = \frac{1}{2}\), \(B = 1\), and \(C = -\pi\).

Determine the amplitude \(A\), which is the absolute value of the coefficient in front of the sine function: \(A = \left| \frac{1}{2} \right|\).

Calculate the period using the formula \(\text{Period} = \frac{2\pi}{B}\). Since \(B = 1\), the period is \(2\pi\).

Find the phase shift \(C\), which is the horizontal shift of the graph. Since \(C = -\pi\), the graph shifts \(\pi\) units to the left. Use this information to sketch one full period of the sine wave starting from \(x = -\pi\) to \(x = -\pi + 2\pi = \pi\).

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주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Amplitude of a Sine Function

Amplitude is the maximum absolute value of the sine function's output, representing the height from the midline to the peak. For y = (1/2) sin(x + π), the amplitude is 1/2, indicating the wave oscillates between -1/2 and 1/2.

Period of a Sine Function

The period is the length of one complete cycle of the sine wave, calculated as 2π divided by the coefficient of x inside the function. Since the coefficient of x is 1 in y = (1/2) sin(x + π), the period remains 2π.

Phase Shift of a Sine Function

Phase shift is the horizontal translation of the sine curve, determined by solving (x + π) = 0, giving a shift of -π. This means the graph is shifted π units to the left compared to the standard sine function.

Determine the amplitude, period, and phase shift of each function. Then graph one period of the function.y = 1/2 sin(x + π)