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Ch. 2 - Acute Angles and Right Triangles
Lial - Trigonometry 12th Edition
Lial12th EditionTrigonometryISBN: 9780136552161당신이 사용하는 게 아니라요?교과서 변경
3장, 문제 31

Find one solution for each equation. Assume all angles involved are acute angles. See Example 3. tan α = cot(α + 10°)

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1
Recall the definition of cotangent in terms of tangent: \(\cot \theta = \frac{1}{\tan \theta}\). So, rewrite the equation \(\tan \alpha = \cot(\alpha + 10^\circ)\) as \(\tan \alpha = \frac{1}{\tan(\alpha + 10^\circ)}\).
Multiply both sides of the equation by \(\tan(\alpha + 10^\circ)\) to eliminate the fraction: \(\tan \alpha \cdot \tan(\alpha + 10^\circ) = 1\).
Use the tangent addition formula to express \(\tan(\alpha + 10^\circ)\) in terms of \(\tan \alpha\) and \(\tan 10^\circ\): \(\tan(\alpha + 10^\circ) = \frac{\tan \alpha + \tan 10^\circ}{1 - \tan \alpha \tan 10^\circ}\).
Substitute this expression back into the equation from step 2: \(\tan \alpha \cdot \frac{\tan \alpha + \tan 10^\circ}{1 - \tan \alpha \tan 10^\circ} = 1\).
Multiply both sides by the denominator to clear the fraction and then rearrange the resulting equation to form a quadratic equation in terms of \(\tan \alpha\). Solve this quadratic equation to find possible values of \(\tan \alpha\), and then determine \(\alpha\) by taking the arctangent, considering that \(\alpha\) is an acute angle.

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주요 개념

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Tangent and cotangent are reciprocal trigonometric functions, where tan(θ) = 1/cot(θ). Understanding that cotangent of an angle can be expressed as the tangent of its complement, cot(θ) = tan(90° - θ), helps in rewriting and solving equations involving both functions.
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Solving trigonometric equations involves manipulating the equation using identities and algebraic techniques to isolate the variable. Recognizing equivalent expressions and applying inverse functions or angle relationships is essential to find valid angle solutions within given constraints.
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When angles are restricted to acute angles (0° < angle < 90°), solutions must be checked to ensure they fall within this range. This constraint limits possible solutions and affects how inverse trigonometric functions are applied, ensuring the final answer is valid in the given context.
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