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Ch. 3 - Radian Measure and The Unit Circle
Lial - Trigonometry 12th Edition
Lial12th EditionTrigonometryISBN: 9780136552161당신이 사용하는 게 아니라요?교과서 변경
4장, 문제 73

Find the exact values of s in the given interval that satisfy the given condition.


[0, 2π) ; sin s = -√3 / 2

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1
Identify the given equation and interval: We need to find all values of \(s\) in the interval \([0, 2\pi)\) such that \(\sin s = -\frac{\sqrt{3}}{2}\).
Recall the reference angle: The value \(\frac{\sqrt{3}}{2}\) is a common sine value corresponding to an angle of \(\frac{\pi}{3}\). Since the sine is negative, we look for angles where sine is negative.
Determine the quadrants where sine is negative: Sine is negative in the third and fourth quadrants. So, the solutions will be angles in these quadrants with reference angle \(\frac{\pi}{3}\).
Write the general solutions for \(s\): In the third quadrant, \(s = \pi + \frac{\pi}{3}\). In the fourth quadrant, \(s = 2\pi - \frac{\pi}{3}\).
Simplify the expressions for \(s\) and verify they lie within the interval \([0, 2\pi)\) to find the exact solutions.

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주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

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