Graph each function over a one-period interval.
y = -½ cos (πx - π)

검증된 단계별 안내

Identify the given function: \(y = -\frac{1}{2} \cos(\pi x - \pi)\).

Recall that the general form of a cosine function is \(y = A \cos(Bx - C)\), where the period is given by \(\frac{2\pi}{|B|}\).

Calculate the period of the function: since \(B = \pi\), the period is \(\frac{2\pi}{\pi} = 2\).

Determine the one-period interval for \(x\). Since the period is 2, a natural choice is any interval of length 2, for example, \([0, 2]\) or \([-1, 1]\).

Analyze the transformations: the amplitude is \(\frac{1}{2}\) (due to the coefficient \(-\frac{1}{2}\)), the negative sign reflects the graph about the x-axis, and the phase shift is found by solving \(\pi x - \pi = 0\) which gives \(x = 1\). This means the graph is shifted right by 1 unit.

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주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Period of a Trigonometric Function

The period is the length of one complete cycle of a trigonometric function. For cosine functions of the form y = cos(bx), the period is calculated as 2π divided by the absolute value of b. Understanding the period helps determine the interval over which to graph the function.

Phase Shift in Trigonometric Functions

Phase shift refers to the horizontal translation of the graph caused by adding or subtracting a constant inside the function's argument. For y = cos(bx - c), the phase shift is c/b. It affects where the graph starts within the period and is essential for accurate plotting.

Amplitude and Reflection

Amplitude is the absolute value of the coefficient multiplying the cosine function, indicating the maximum displacement from the midline. A negative coefficient reflects the graph across the x-axis. In y = -½ cos(πx - π), the amplitude is ½, and the negative sign flips the graph vertically.

Graph each function over a one-period interval.y = -½ cos (πx - π)