Solve each equation for exact solutions.
2 arccos (x/3 - π/3) = 2π

검증된 단계별 안내

Start by isolating the arccosine expression. Given the equation \(2 \arccos\left(\frac{x}{3} - \frac{\pi}{3}\right) = 2\pi\), divide both sides by 2 to get \(\arccos\left(\frac{x}{3} - \frac{\pi}{3}\right) = \pi\).

Recall the definition and range of the arccosine function: \(\arccos(y)\) returns an angle \(\theta\) such that \(\cos(\theta) = y\) and \(\theta \in [0, \pi]\). Here, \(\arccos\left(\frac{x}{3} - \frac{\pi}{3}\right) = \pi\) means the angle whose cosine is \(\frac{x}{3} - \frac{\pi}{3}\) is \(\pi\).

Use the property of cosine: \(\cos(\pi) = -1\). Set the inside of the arccos equal to \(\cos(\pi)\), so \(\frac{x}{3} - \frac{\pi}{3} = -1\).

Solve the resulting linear equation for \(x\): multiply both sides by 3 to clear the denominator, then isolate \(x\).

Check the solution to ensure it lies within the domain of the arccos function, which requires the argument \(\frac{x}{3} - \frac{\pi}{3}\) to be in the interval \([-1, 1]\).

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주요 개념

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Inverse Trigonometric Functions (Arccos)

The arccos function is the inverse of the cosine function, returning the angle whose cosine is a given number. Its principal range is from 0 to π radians. Understanding arccos helps in solving equations where the angle is expressed as arccos of an expression.

Solving Trigonometric Equations

Solving trigonometric equations involves isolating the trigonometric function and finding all angles that satisfy the equation within the function's domain. This often requires using inverse functions and considering the periodicity of trigonometric functions to find all solutions.

Domain and Range Restrictions

When dealing with inverse trig functions, it is crucial to consider the domain of the original function and the range of the inverse function. For arccos, the input must be between -1 and 1, and the output angle lies between 0 and π, which restricts possible solutions.

Solve each equation for exact solutions.2 arccos (x/3 - π/3) = 2π