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Ch. 6 - Inverse Circular Functions and Trigonometric Equations
Lial - Trigonometry 12th Edition
Lial12th EditionTrigonometryISBN: 9780136552161당신이 사용하는 게 아니라요?교과서 변경
7장, 문제 6.3.29

Solve each equation in x over the interval [0, 2π) and each equation in θ over the interval [0°, 360°). Give exact solutions.
8 sec² x/2 = 4

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Start with the given equation: \(8 \sec^{2} \frac{x}{2} = 4\).
Divide both sides of the equation by 8 to isolate \(\sec^{2} \frac{x}{2}\): \(\sec^{2} \frac{x}{2} = \frac{4}{8} = \frac{1}{2}\).
Recall the identity \(\sec \theta = \frac{1}{\cos \theta}\), so \(\sec^{2} \theta = \frac{1}{\cos^{2} \theta}\). Substitute this into the equation to get \(\frac{1}{\cos^{2} \frac{x}{2}} = \frac{1}{2}\).
Invert both sides to solve for \(\cos^{2} \frac{x}{2}\): \(\cos^{2} \frac{x}{2} = 2\).
Analyze the equation \(\cos^{2} \frac{x}{2} = 2\) and determine if there are any real solutions for \(x\) in the interval \([0, 2\pi)\), considering the range of the cosine function.

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