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Ch. 6 - Inverse Circular Functions and Trigonometric Equations
Lial - Trigonometry 12th Edition
Lial12th EditionTrigonometryISBN: 9780136552161당신이 사용하는 게 아니라요?교과서 변경
7장, 문제 6.3.27

Solve each equation in x over the interval [0, 2π) and each equation in θ over the interval [0°, 360°). Give exact solutions.
sin x = sin 2x

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Start with the given equation: \(\sin x = \sin 2x\).
Recall the identity that if \(\sin A = \sin B\), then the solutions are given by two cases: \(A = B + 2k\pi\) or \(A = \pi - B + 2k\pi\), where \(k\) is any integer.
Apply this identity to the equation by setting \(x = 2x + 2k\pi\) and \(x = \pi - 2x + 2k\pi\) separately.
Solve each resulting equation for \(x\) within the interval \([0, 2\pi)\) by isolating \(x\) and considering integer values of \(k\) that keep \(x\) in the interval.
List all values of \(x\) found from both cases that lie within \([0, 2\pi)\) as the exact solutions.

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주요 개념

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When solving trigonometric equations, solutions must be restricted to the given interval, such as [0, 2π) for radians or [0°, 360°) for degrees. Understanding how to express solutions within these intervals ensures the answers are complete and conform to the problem's requirements.
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