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Ch. R - Algebra Review
Lial - Trigonometry 12th Edition
Lial12th EditionTrigonometryISBN: 9780136552161당신이 사용하는 게 아니라요?교과서 변경
1장, 문제 R.3.7

CONCEPT PREVIEW Work each problem. Match each polynomial in Column I with its factored form in Column II. I II a. 8x³ - 27 A. (3 - 2x) (9 + 6x + 4x²) b. 8x³ + 27 B. (2x - 3) (4x² + 6x + 9) c. 27 - 8x³ C. (2x + 3) (4x² - 6x + 9)

검증된 단계별 안내
1
Recognize that each polynomial in Column I is a difference or sum of cubes. Recall the formulas for factoring cubes: for difference of cubes, \(a^3 - b^3 = (a - b)(a^2 + ab + b^2)\), and for sum of cubes, \(a^3 + b^3 = (a + b)(a^2 - ab + b^2)\).
Identify \(a\) and \(b\) for each polynomial by expressing the terms as cubes. For example, \$8x^3\( can be written as \)(2x)^3\( and \(27\) as \)3^3$.
Apply the difference of cubes formula to \(8x^3 - 27\) and \(27 - 8x^3\), noting the order of subtraction affects the signs in the factors.
Apply the sum of cubes formula to \(8x^3 + 27\), carefully substituting \(a = 2x\) and \(b = 3\) into the formula.
Match each factored form from Column II to the corresponding polynomial in Column I by comparing the factors obtained from the formulas with the given options.

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주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Sum and Difference of Cubes

The sum and difference of cubes are special polynomial forms that factor into binomial and trinomial products. For example, a³ + b³ factors as (a + b)(a² - ab + b²), and a³ - b³ factors as (a - b)(a² + ab + b²). Recognizing these forms helps in quickly factoring cubic expressions.
추천 영상:
4:47
Sum and Difference of Tangent

Identifying 'a' and 'b' in Cubic Expressions

To factor cubic polynomials using sum or difference of cubes, it is essential to identify the cube roots of each term. For instance, in 8x³, the cube root is 2x, and in 27, it is 3. Correctly determining these values allows proper application of the factoring formulas.
추천 영상:
6:36
Simplifying Trig Expressions

Matching Factored Forms to Original Polynomials

After factoring, it is important to verify the factored form by expanding it back to the original polynomial. This ensures the correct pairing between the polynomial and its factorization, especially when multiple similar options are given, as in matching problems.
추천 영상:
03:55
Position Vectors & Component Form