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Ch. R - Algebra Review
Lial - Trigonometry 12th Edition
Lial12th EditionTrigonometryISBN: 9780136552161당신이 사용하는 게 아니라요?교과서 변경
1장, 문제 49

Find each root. See Example 3. ∛0.001

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Recognize that the problem asks for the cube root of 0.001, which means finding a number \( x \) such that \( x^3 = 0.001 \).
Express 0.001 as a power of 10: \( 0.001 = 10^{-3} \). This helps simplify the root calculation using exponent rules.
Use the property of roots and exponents: \( \sqrt[3]{10^{-3}} = 10^{\frac{-3}{3}} \). This means you divide the exponent by the root's degree.
Simplify the exponent: \( 10^{\frac{-3}{3}} = 10^{-1} \).
Rewrite \( 10^{-1} \) as a decimal: \( 10^{-1} = 0.1 \), which is the cube root of 0.001.

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주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Cube Roots

The cube root of a number is a value that, when multiplied by itself three times, gives the original number. For example, the cube root of 8 is 2 because 2 × 2 × 2 = 8. It is denoted as ∛x.
추천 영상:
07:37
Complex Roots

Decimal Representation and Powers of Ten

Understanding decimals and their relation to powers of ten helps simplify root calculations. For instance, 0.001 can be written as 10⁻³, making it easier to apply root operations using exponent rules.
추천 영상:
03:41
Powers Of Complex Numbers In Polar Form (DeMoivre's Theorem)

Properties of Exponents in Root Extraction

Roots can be expressed as fractional exponents, such as ∛x = x^(1/3). Applying this property allows converting roots into exponent form, facilitating calculations especially with powers of ten or other numbers.
추천 영상:
2:20
Imaginary Roots with the Square Root Property