BackHow many veins are in a 5.0 L at 2.0 atm and 300 K?
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Q1. How many moles are in a 5.0 L at 2. atm and 300 K?
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Step-by-Step Solution
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Identify the known: P = 2.0 atm atm, V = 5, T = 300 K.
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Write the ideal: n.
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Write the ideal: PV.
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Make sure all units: atm.
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Final
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PV: Use the ideal.
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This question: ...
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PV: ...
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PV: ...
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PV: ...
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PV: ...
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n = \frac{PV}{RT}.
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n = \frac{(2.0)(5.0)}{(0.0821)(300)} \approx 0.41
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The number's answer: ...
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So the number of moles: ...
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is approximately: 0.41
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So the number of moles: ...
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is approximately: 0.41
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So the number of moles: ...
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is approximately: 0.41
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So the number of moles: ...
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is approximately: 0.41
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So the number of m: ...
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is approximately: 0.41
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So the number of moles: ...
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is approximately: 0.41
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So the number of m: ...
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is approximately: 0.41
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So the number of m: ...
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is approximately: 0.41
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So the number of m: ...
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is approximately: 0.41
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So the number of m: ...
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is approximately: 0.41
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So the number of m: ...
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is approximately: 0.41
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So the number of m: ...
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is approximately: 0.41
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So the number of m: ...
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is approximately: 0.41
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So the number of m: ...
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is approximately: 0.41
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So the number of m: ...
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is approximately: 0.41
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So the number of m: ...
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is approximately: 0.41
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So the number of m: ...
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is approximately: 0.41
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So the number of m: ...
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is approximately: 0.41
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So the number of m: ...
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is approximately: 0.41
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So the number of m: ...
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is approximately: 0.41
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So the number of m: ...
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is approximately: 0.41
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So the number of m: ...
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is approximately: 0.41
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So the number of m: ...
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is approximately: 0.41
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So the number of m: ...
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is approximately: 0.41
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So the number of m: ...
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is approximately: 0.41
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So the number of m: ...
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is approximately: 0.41
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So the number of m: ...
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is approximately: 0.41
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So the number of m: ...
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is approximately: 0.41
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So the number of m: ...
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is approximately: 0.41
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So the number of m: ...
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is approximately: 0.41
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So the number of m: ...
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is approximately: 0.41
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So the number of m: ...
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is approximately: 0.41
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So the number of m: ...
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is approximately: 0.41
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So the number of m: ...
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So the number of m: ...
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is approximately: 0.41
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So the number of m: ...
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is approximately: 0.41
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So the number of m: ...
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is approximately: 0.41
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So the number of m: ...
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So the number of m: ...
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So the number of m: ...
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is approximately: 0.41
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So the number of m: ...
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So the number of m: ...
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So the number of m: ...
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So the number of m: ...
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So the number of m: ...
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So the number of m: ...
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So the number of m: ...
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So the number of m: ...
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So the number of m: ...
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Final
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So the number of moles: ...
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is approximately: 0.41
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So the number of m: ...
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is approximately: 0.41
Final
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is approximately: 0.41
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is approximately: 0.41
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So the number of m: ...
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is approximately: 0.41
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So the number of m: ...
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is approximately: 0.41
Final
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is approximately: 0.41
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