Q: Which formula correctly calculates the total magnification of a microscope?

$\text{Total Magnification} = \text{Ocular Magnification} \times \text{Objective Magnification}$

Q: If the field diameter under low power (10x objective) is 4 mm, what is the field diameter under high power (40x objective)?

$\text{Field Diameter}_{\text{high}} = \frac{\text{Field Diameter}_{\text{low}} \times \text{Objective}_{\text{low}}}{\text{Objective}_{\text{high}}} = \frac{4 \times 10}{40} = 1 \text{ mm}$

Q: If the field diameter at 10x objective is 5 mm, and you switch to a 40x objective, how much of the field will you see?

$\frac{5 \times 10}{40} = 1.25 \text{ mm}$

Question 1

Which part of the compound microscope is responsible for adjusting the amount of light that reaches the specimen?

Accepted Answer

Iris diaphragm

Question 2

If you are using a 10x ocular lens and a 40x objective lens, what is the total magnification of the specimen?

Accepted Answer

$10 	imes 40 = 400$

Question 3

When switching from low power to high power objective, what happens to the field diameter?

Accepted Answer

It decreases

Question 4

A student observes a specimen under the microscope and moves the slide to the left. In which direction does the image appear to move?

Accepted Answer

To the right

Question 5

Which formula correctly calculates the total magnification of a microscope?

Accepted Answer

$	ext{Total Magnification} = 	ext{Ocular Magnification} 	imes 	ext{Objective Magnification}$

Question 6

If the field diameter under low power (10x objective) is 4 mm, what is the field diameter under high power (40x objective)?

Accepted Answer

$	ext{Field Diameter}_{	ext{high}} = \frac{	ext{Field Diameter}_{	ext{low}} 	imes 	ext{Objective}_{	ext{low}}}{	ext{Objective}_{	ext{high}}} = \frac{4 	imes 10}{40} = 1 	ext{ mm}$

Question 7

Which of the following best describes a parfocal microscope?

Accepted Answer

It keeps the specimen in focus when changing objectives

Question 8

Why is it important to start focusing with the scanning objective (lowest power) before moving to higher magnifications?

Accepted Answer

It provides a wider field of view and reduces the risk of damaging the slide or objective lens

Question 9

Which statement about resolution in microscopy is correct?

Accepted Answer

Resolution is the ability to distinguish two close objects as separate

Question 10

A student is using a compound microscope and wants to calculate the working distance. Which definition is correct?

Accepted Answer

The distance between the objective lens and the specimen

Question 11

If the total magnification is 1000x and the resolution limit is $0.2 \mu m$, what is the smallest distance between two points that can be distinguished?

Accepted Answer

$0.2 \mu m$

Question 12

When using oil immersion, what is the main purpose of the immersion oil?

Accepted Answer

To increase the resolution by reducing light refraction

Question 13

Which of the following is NOT a proper technique for handling a compound microscope?

Accepted Answer

Leaving the microscope with the objective lens touching the slide

Question 14

A student observes a letter 'e' under the microscope. When the slide is moved away from the student, in which direction does the image move?

Accepted Answer

Toward the student

Question 15

If the field diameter at 10x objective is 5 mm, and you switch to a 40x objective, how much of the field will you see?

Accepted Answer

$\frac{5 	imes 10}{40} = 1.25 	ext{ mm}$

Question 16

Which part of the microscope is used to bring the specimen into sharp focus under high power?

Accepted Answer

Fine adjustment knob

Question 17

Why is it better to decrease the light intensity when changing to a higher objective lens?

Accepted Answer

To improve contrast and prevent glare, making details easier to see

Question 18

Which of the following best explains the concept of 'virtual image' in light microscopy?

Accepted Answer

The image formed by the ocular lens that can be seen by the eye

Question 19

A student wants to estimate the size of a cell under the microscope. If the field diameter is 2 mm and approximately 8 cells fit across the field, what is the average size of one cell?

Accepted Answer

$\frac{2 	ext{ mm}}{8} = 0.25 	ext{ mm}$

Question 20

Which of the following is a correct statement about the relationship between magnification and working distance?

Accepted Answer

As magnification increases, working distance decreases

Microscopy in Anatomy & Physiology: Structure, Function, and Techniques

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