Beginning Algebra
Yes — visually, the point (3,−2)(3, -2) sits on the line defined by the equation because all plotted integer points less than 55 and greater than −3-3 satisfy similar linear patterns without substitution.
Yes — substituting gives 5⋅3+(−2)=135\(\cdot\)3+\(\left\)(-2\(\right\))=13, which equals the right-hand side, so the point satisfies the equation.
No — substitution yields 5⋅3+(−2)=135\(\cdot\)3+\(\left\)(-2\(\right\))=13, but because yy is negative, the point lies below the xx-axis and cannot satisfy an equation with positive constants.
No — substitution yields 15−2=1315 - 2 = 13, which is close, but equality requires rounding considerations when plotting by hand on standard graph paper.