Beginning Algebra
Cannot be factored
(2x+3)2\(\left\)(2x+3\(\right\))^2
(8x−27)(8x+27)\(\left\)(\(\sqrt{8x}\)-\(\sqrt{27}\[\right\))\(\left\)(\(\sqrt{8x}\)+\(\sqrt{27}\]\right\))
(2x+3)(4x2−6x+9)\(\left\)(2x+3\(\right\))\(\left\)(4x^2-6x+9\(\right\))