bb51159c-ion-e-25t2-49-factor-e-and-state-how-this-factoring-simplifies-solving-

Question

A physics problem gives the energy expression E=25t2−49E=$$25t^2-49. $$Factor EE, then solve for tt when E=0E = 0.

Accepted Answer

﻿E=(5t−7)(5t+7)E = (5t − 7)(5t + 7)E=(5t−7)(5t+7)﻿﻿E=0E=0E=0﻿ for t=±75t=\pm\frac75

Answer

E=(5t−7)(5t+7)E = (5t − 7)(5t + 7)E=0E=0 for t=±7t=\pm7

Answer

E=(25t−7)(t+7)E=(25t-7)(t+7)﻿E=0E=0E=0﻿ for t=725t=\frac{7}{25} or t=−7t=-7

Answer

EE cannot be factored, so that tt has no real solutions

A physics problem gives the energy expression E=25t2−49E=25t^2-49. Factor EE, then solve for tt when E=0E = 0.