given-a-function-hthlefttright-that-models-the-height-in-centimeters-of-a-plant-

Question

Given a function $H (t)$ that models the height (in centimeters) of a plant $t$ days after it was planted, estimate $H prime of 90$ from the provided graph. What does this derivative indicate?

Accepted Answer

$H^{\prime}\left(90 ight)=\frac15$

At $t=90 ext{ days}$ , the plant is growing at a rate of $\frac15 ext{ cm/day}$ .

Answer

$H^{'} (90) = - \frac{1}{5}$

At $t=90 ext{ days}$ , the plant is shrinking at a rate of $\frac15 ext{ cm/day}$ .

Answer

$H^{\prime}\left(90 ight)=\frac15$

At $t=90 ext{ days}$ , the plant is growing at a rate of $5 cm slash day$ .

Answer

$H^{\prime}\left(90 ight)=\frac15$

At $t=90 ext{ days}$ , the plant is shrinking at a rate of $5 ext{ cm/day}$ .

Given a function H(t)H\left(t\right) that models the height (in centimeters) of a plant tt days after it was planted, estimate H′(90)H^{\prime}\left(90\right) from the provided graph. What does this derivative indicate?

Given a function $H (t)$ that models the height (in centimeters) of a plant $t$ days after it was planted, estimate $H prime of 90$ from the provided graph. What does this derivative indicate?