find-the-interval-for-the-continuity-of-the-function-also-identify-the-endpoints

Question

Find the interval of continuity for function. Also, identify the endpoints for which the function is left-continuous or right-continuous.

$g (x) = \sqrt{289 - x^{2}}$

Accepted Answer

$open bracket negative 17 comma 17 close bracket$ ,

Left-continuous at $negative 17$ , right-continuous at $17$

Answer

$open bracket negative 17 comma 17 close bracket$ ,

Left-continuous at $negative 17$ , right-continuous at $17$

Answer

$\left\lbrack-289,289\right\rbrack$ ,

Left-continuous at $289$ , right-continuous at $negative 289$

Answer

$\left\lbrack-289,289\right\rbrack$ ,

Left-continuous at $289$ , right-continuous at $negative 289$

Find the interval of continuity for function. Also, identify the endpoints for which the function is left-continuous or right-continuous.g(x)=289−x2g\(\left\)(x\(\right\))=\(\sqrt{289-x^2}\)