use-the-following-theorem-to-evaluate-limx0sin39x9xdisplaystyle-limx-to-0fracsin

Question

Use the following theorem to evaluate $\lim_{x \to 0} \frac{\sin 39 x}{9 x}$ :

$\lim_{x \to 0} \frac{\sin x}{x} = 1$

Accepted Answer

$\frac{13}{3}$

Answer

$\frac{13}{3}$

Answer

$\frac{13}{3}$

Answer

$\frac{13}{3}$

Use the following theorem to evaluate limx→0sin39x9x\displaystyle \lim_{x \to 0}{\frac{\sin{39x}}{9x}}:limx→0sinxx=1\displaystyle \lim_{x \to 0}{\frac{\sin{x}}{x}}=1