Find the extreme values of $f\left(x\right)=\frac{242}{5}{x}^5-\frac{3874}{3}{x}^3+32x$. Round to two decimal places if necessary.

• A. Local minima: $-1.94$ at $x=-\(\frac{1}{11}\)$ and $-32955.73$ at $x=4$Local maxima: $32955.73$ at $x=-4$ and $1.94$ at $x=\(\frac{1}{11}\)$
• B. Local minima: $-1.94$ at $x=\(\frac{1}{11}\)$ and $-32955.73$ at $x=4$Local maxima: $32955.73$ at $x=-4$ and $1.94$ at $x=-\(\frac{1}{11}\)$
• C. Local minima: $-1.32$ at $x=-\(\frac{1}{22}\)$ and $-16288.73$ at $x=2$Local maxima: $16288.73$ at $x=-2$ and $1.32$ at $x=\(\frac{1}{22}\)$
• D. Local minima: $-1.32$ at $x=\(\frac{1}{22}\)$ and $-16288.73$ at $x=2$Local maxima: $16288.73$ at $x=-2$ and $1.32$ at $x=-\(\frac{1}{22}\)$

Answer: (A)