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Question

Determine the linear approximation of $h (y) = \sqrt{4 y - 5}$ at the point $a equals 2$ .

Accepted Answer

$L (y) = \frac{2 \sqrt{3}}{3} y - \frac{\sqrt{3}}{3}$

Answer

$L (y) = \frac{2 \sqrt{3}}{3} y - \frac{\sqrt{3}}{3}$

Answer

$L (y) = \frac{2 \sqrt{3}}{3} y - \frac{\sqrt{3}}{3}$

Answer

$L (y) = \frac{2 \sqrt{3}}{3} y - \frac{\sqrt{3}}{3}$

Determine the linear approximation of h(y)=4y−5h(y)=\sqrt{4y - 5} at the point a=2a=2.