Calculus
f−1(x)=17x−57f^{-1}\left(x\right)=\frac17x-\frac57
f−1(x)=17x+57f^{-1}\left(x\right)=\frac17x+\frac57
f−1(x)=17x+5f^{-1}\left(x\right)=\frac17x+5
f−1(x)=17x−5f^{-1}\left(x\right)=\frac17x-5