Calculus
a=7,a=7, the function is discontinuous because limx→af(x)≠f(a)\(\lim\)_{x\(\to\) a}f\(\left\)(x\(\right\))\(\ne\) f\(\left\)(a\(\right\)); a=9,a=9, the function is discontinuous because the limit does not exist; a=15,a=15, the function is discontinuous because f(a)f\(\left\)(a\(\right\)) is undefined where aa is in the domain of ff
a=5,a=5, the function is discontinuous because the limit does not exist ff; a=7,a=7, the function is discontinuous because limx→af(x)≠f(a)\(\lim\)_{x\(\to\) a}f\(\left\)(x\(\right\))\(\ne\) f\(\left\)(a\(\right\)); a=9,a=9, the function is discontinuous because f(a)f\(\left\)(a\(\right\)) is undefined where aa is in the domain of ff
a=0,a=0, the function is discontinuous because f(a)f\(\left\)(a\(\right\)) is undefined where aa is in the domain of ff; a=7,a=7, the function is discontinuous because limx→af(x)≠f(a)\(\lim\)_{x\(\to\) a}f\(\left\)(x\(\right\))\(\ne\) f\(\left\)(a\(\right\)); a=9,a=9, the function is discontinuous because the limit does not exist
a=5,a=5, the function is discontinuous because f(a)f\(\left\)(a\(\right\)) is undefined where aa is in the domain of ff; a=7,a=7, the function is discontinuous because limx→af(x)≠f(a)\(\lim\)_{x\(\to\) a}f\(\left\)(x\(\right\))\(\ne\) f\(\left\)(a\(\right\)); a=9,a=9, the function is discontinuous because the limit does not exist