Calculus
V′(10)=4V^{\prime}(10)=4 m3/s\text{ m}^3\text{/s}
The rate of change of the volume of the balloon is 4 m3/s4\text{ m}^3\text{/s} at t=10t=10 s\text{ s}.
V′(10)=10V^{\prime}\left(10\right)=10 m3/s\text{ m}^3\text{/s}
The rate of change of the volume of the balloon is 1010 m3/s\text{ m}^3\text{/s} at t=10t=10 s\text{ s}.
V′(10)=40V^{\prime}\left(10\right)=40 m3/s\text{ m}^3\text{/s}
The rate of change of the volume of the balloon is 4040 m3/s\text{ m}^3\text{/s} at t=10t=10 s\text{ s}.
V′(10)=5V^{\prime}\left(10\right)=5 m3/s\text{ m}^3\text{/s}
The rate of change of the volume of the balloon is 55 m3/s\text{ m}^3\text{/s} at t=10t=10 s\text{ s}.