BackCalculus Quiz Guidance: Limits and Squeeze Theorem
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Q1. Evaluate the limit: $$\lim_{h \to 0} \frac{f(-2 + h) - f(-2)}{h}$$ where $$f(x) = 6x^2 + 6$$.
Background
Topic: Definition of the Derivative / Limits
This question tests your understanding of the limit definition of the derivative at a point, specifically using the difference quotient. It also checks your ability to substitute and simplify expressions involving functions.
Key Terms and Formulas:
Difference Quotient: $$\frac{f(a + h) - f(a)}{h}$$
Limit: $$\lim_{h \to 0}$$
Quadratic Function: $$f(x) = 6x^2 + 6$$
Step-by-Step Guidance
Start by substituting $a = -2$ into the difference quotient: $$\frac{f(-2 + h) - f(-2)}{h}$$
Calculate $f(-2 + h)$: $$f(-2 + h) = 6(-2 + h)^2 + 6$$
Expand $(-2 + h)^2$ to get $h^2 - 4h + 4$, then substitute back: $$f(-2 + h) = 6(h^2 - 4h + 4) + 6$$
Calculate $f(-2)$: $$f(-2) = 6(-2)^2 + 6 = 6 \cdot 4 + 6 = 24 + 6 = 30$$
Set up the difference quotient: $$\frac{[6(h^2 - 4h + 4) + 6] - 30}{h}$$
Try solving on your own before revealing the answer!
Q2. Suppose $$8x - 20 \leq f(x) \leq x^2 + 4x - 16$$. Use this to compute $$\lim_{x \to 2} f(x)$$.
Background
Topic: Squeeze Theorem / Limits
This question is about using the Squeeze Theorem to find the limit of a function that is bounded between two other functions. The Squeeze Theorem is a fundamental concept in calculus for evaluating limits when direct substitution is not possible.
Key Terms and Formulas:
Squeeze Theorem: If $g(x) \leq f(x) \leq h(x)$ and $\lim_{x \to a} g(x) = \lim_{x \to a} h(x) = L$, then $\lim_{x \to a} f(x) = L$.
Limit of a polynomial: Polynomials are continuous, so $\lim_{x \to a} p(x) = p(a)$.
Step-by-Step Guidance
Write the inequalities: $$8x - 20 \leq f(x) \leq x^2 + 4x - 16$$
Take the limit as $x \to 2$ for each part: $$\lim_{x \to 2} (8x - 20) \leq \lim_{x \to 2} f(x) \leq \lim_{x \to 2} (x^2 + 4x - 16)$$
Evaluate the left and right limits using direct substitution: $$8 \cdot 2 - 20$$ and $$2^2 + 4 \cdot 2 - 16$$
Simplify both expressions to see if they yield the same value.