Exercises 137–139 will help you prepare for the material covered in the next section. Solve: (x + 2)/(4x + 3) = 1/x
Table of contents
- 0. Review of Algebra4h 18m
- 1. Equations & Inequalities3h 18m
- 2. Graphs of Equations1h 43m
- 3. Functions2h 17m
- 4. Polynomial Functions1h 44m
- 5. Rational Functions1h 23m
- 6. Exponential & Logarithmic Functions2h 28m
- 7. Systems of Equations & Matrices4h 5m
- 8. Conic Sections2h 23m
- 9. Sequences, Series, & Induction1h 22m
- 10. Combinatorics & Probability1h 45m
6. Exponential & Logarithmic Functions
Solving Exponential and Logarithmic Equations
Problem 84
Textbook Question
Use the formula for continuous compounding to solve Exercises 84–85. How long, to the nearest tenth of a year, will it take \$50,000 to triple in value at an annual rate of 7.5% compounded continuously?
Verified step by step guidance1
Identify the formula for continuous compounding: \( A = P e^{rt} \), where \( A \) is the future value, \( P \) is the principal, \( r \) is the annual interest rate (in decimal form), \( t \) is the time in years, and \( e \) is the base of the natural logarithm.
Substitute the known values into the formula: \( A = 3P \) (since the value triples), \( P = 50000 \), and \( r = 0.075 \). The equation becomes \( 3(50000) = 50000 e^{0.075t} \).
Simplify the equation by dividing both sides by \( 50000 \): \( 3 = e^{0.075t} \).
Take the natural logarithm (\( \ln \)) of both sides to isolate \( t \): \( \ln(3) = 0.075t \).
Solve for \( t \) by dividing both sides by \( 0.075 \): \( t = \frac{\ln(3)}{0.075} \). This will give the time in years to the nearest tenth.
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Continuous Compounding
Continuous compounding refers to the process of earning interest on an investment at every possible moment, rather than at discrete intervals. The formula used for continuous compounding is A = Pe^(rt), where A is the amount of money accumulated after time t, P is the principal amount, r is the annual interest rate, and e is the base of the natural logarithm. This method allows for the maximum growth of an investment over time.
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Exponential Growth
Exponential growth occurs when the growth rate of a value is proportional to its current value, leading to rapid increases over time. In the context of finance, this is often modeled using the exponential function, which reflects how investments grow when interest is compounded continuously. Understanding this concept is crucial for predicting how long it will take for an investment to reach a certain value.
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Natural Logarithm
The natural logarithm, denoted as ln, is the logarithm to the base e (approximately 2.71828). It is particularly useful in solving equations involving exponential growth, such as those found in continuous compounding. When determining the time required for an investment to grow to a specific amount, the natural logarithm helps isolate the variable t in the continuous compounding formula.
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