Solve the equations containing absolute value in Exercises 94–95....

Question

Solve the equations containing absolute value in Exercises 94–95. |2x+1| = 7

Accepted Answer

Welcome back. I'm so glad you're here. We're solving for X and X is inside an absolute value bracket. When we're dealing with absolute value, what we're doing is imagining a number line and we're seeing how far is something away from zero? Well there's something that we're wondering about is nine units away from zero. So that can be nine which would be nine units away from zero. Or it could be negative nine which also nine units away from zero. So in order to drop those absolute value bars into figure out the absolute value of x minus one is nine units away from zero. We set it to positive nine, X minus one equals positive nine and x minus one equals negative nine. And both of those answers are going to give us the nine units away from zero. We will just solve this as we normally would solve for X. Now add one to both sides, so X equals negative nine plus one is negative eight. And at wonderful sides. Over here we've got X equals nine plus one which is 10. Both of those values negative eight and 10 could be plugged into X and make it true for the absolute value of X minus one equals 99 units away from zero. We look at our answer choices and that is answer choice D Well done. We'll catch you on the next one

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