Consider a line defined by 6x + 2y = 3. Write equations (both in standard and slope-intercept form) of a line that is perpendicular to the given line and passes through (2,5). 

• A. Standard form: x + 3y = -13; Slope-intercept form: y = -(1/3)x - 13/3
• B. Standard form: x - 3y = -13; Slope-intercept form: y = (1/3)x + 13/3
• C. Standard form: x + 3y = 13; Slope-intercept form: y = -(1/3)x + 13/3
• D. Standard form: x - 3y = 13; Slope-intercept form: y = (1/3)x - 13/3

Answer: (B)