Determine the energy produced per mole of U-235 in the following fission reaction:
¹₀n + ²³⁵₉₂U → ¹⁴⁰₅₄Xe + ⁹⁴₃₈Sr + 2 ¹₀n


The atomic masses are given below:
m_U-235 = 235.04392 amu
m_Xe-140 = 139.92164 amu
m_Sr-94 = 93.91535 amu
m_n = 1.00866 amu

• A. 3.2923 x 10^-28 J/mol
• B. 1.7818 x 10^-13 J/mol
• C. 2.9589 x 10^-11 J/mol
• D. 1.7818 x 10¹³ J/mol