Using the following data, 
P_N2 = P_PH3 = 0.06 atm, P_NH3= 0.3 atm, P_P4 = 0.2 atm
ΔG°_{f, P4(g)} = 24.4 kJ/mol, ΔG°_{f, NH3(g)} = –16.4, ΔG°_{f, PH3(g)} = 13.5 kJ/mol, ΔG°_{f, N2(g)} = 0
calculate K_p and ΔG at 298 K for the reaction 
4 PH₃ (g) + 2 N₂ (g) ⇌  P₄ (g) + 4 NH₃ (g)

• A. ΔG = −69.3 kJ
  K_p = 5×10¹⁶
• B. ΔG = 69.3 kJ
  K_p = 1×10¹²
• C. ΔG = −95.2 kJ
  K_p = 5×10¹⁶
• D. ΔG = 95.2 kJ
  K_p = 1×10¹²