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7. Energy, Rate and Equilibrium - Part 3 of 3
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7. Energy, Rate and Equilibrium - Part 3 of 3
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7. Energy, Rate and Equilibrium / The Equilibrium Constant / Problem 2
Problem 2
Consider the following equilibrium:
F
2
(g) ⇌ 2 F (g); K
eq
= 7.40×10
−13
at 500 Kelvin
Calculate [F
2
] at equilibrium when [F] = 5.25 × 10
−4
M.
A
5.25×10
3
mol/L
B
5.25×10
4
mol/L
C
3.72×10
5
mol/L
D
7.09×10
8
mol/L
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