372de24d-expand-12-x-32-showing-careful-handling-of-the-fractional-coefficient

Question

Expand (12x+3)2\left({\displaystyle\frac{1}{2}x+3}\$$right)^2.$$

Accepted Answer

14x2+3x+9\displaystyle \frac{1}{4}$$x^2 + 3x + 9$$

Answer

12x2+3x+9\displaystyle \frac{1}{2}$$x^2 + 3x + 9$$

Answer

14x2+32x+9\displaystyle \frac{1}{4}$$x^2$$ + \frac{3}{2}x + 9

Answer

14x2+6x+9\displaystyle\frac{1}{4}$$x^2+6x+9$$

Expand (12x+3)2\(\left\)({\(\displaystyle\]\frac{1}{2}\)x+3}\(\right\))^2.