ast-common-denominator-lcd-for-expressions-with-denominators-x2-5x-6-x-2-and-x-3

Question

Solve the following rational equation for xx:1x2−5x+6+1x−2=1x+3\displaystyle\frac{1}{$$x^2 - 5x + 6$$}+\frac{1}{x - 2}=\frac{1}{x + 3}

Accepted Answer

No solution

Answer

x=−2x=-2x=2x=2

Answer

x=2x=2 only

Answer

x=−2x=-2 only

Solve the following rational equation for xx:1x2−5x+6+1x−2=1x+3\(\displaystyle\]\frac{1}{x^2 - 5x + 6}\)+\(\frac{1}{x - 2}\)=\(\frac{1}{x + 3}\)