cb4a6748-find-the-center-of-the-hyperbola-x-4216-y-3225-1

Question

Find the center of the hyperbola (x−4)216−(y+3)225=1\frac{\left(x-4\$$right)^2$$}{16}-\frac{\left(y+3\$$right)^2$$}{25}=1.

Accepted Answer

(4,−3)(4, -3)

Answer

(4,3)(4, 3)

Answer

(−3,4)(-3, 4)

Answer

(−4,3)(-4, 3)

Find the center of the hyperbola (x−4)216−(y+3)225=1\(\frac{\left(x-4\right)^2}{16}\)-\(\frac{\left(y+3\right)^2}{25}\)=1.