5cd6e311-uation-in-vertex-form-and-show-the-steps-to-derive-the-appropriate-coef

Question

A horizontal parabola has its vertex at the origin and its focus at (4,0)(4, 0). Which equation represents this parabola?

Accepted Answer

x=116y2\displaystyle x = \frac{1}{16}$$y^2$$

Answer

y=116x2\displaystyle y = \frac{1}{16}$$x^2$$

Answer

x=14y2\displaystyle\displaystyle x=\frac{1}{4}$$y^2$$

Answer

x=16y2x = $$16y^2$$