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Chapter 4: Integration – Concepts, Properties, and Applications

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Integration

Antidifferentiation

Antidifferentiation is the process of finding a function whose derivative is the given function. This process is fundamental to integral calculus and forms the basis for evaluating areas, solving differential equations, and modeling real-world phenomena.

  • Antiderivative: If $F(x)$ is an antiderivative of $f(x)$, then $F'(x) = f(x)$.

  • Indefinite Integral: The set of all antiderivatives of $f(x)$ is denoted by $\int f(x) dx = F(x) + C$, where $C$ is the constant of integration.

  • Checking: Differentiate your result to verify it matches the original function.

Basic Rules for Antiderivatives

  • Constant Rule: $\int k\,dx = kx + C$

  • Power Rule: $\int x^n dx = \frac{x^{n+1}}{n+1} + C$, $n \neq -1$

  • Natural Logarithm Rule: $\int \frac{1}{x} dx = \ln|x| + C$

  • Exponential Rule (base $e$): $\int e^{ax} dx = \frac{1}{a} e^{ax} + C$, $a \neq 0$

Examples

  • Example 1: $\int 8 dx = 8x + C$

  • Example 2: $\int 3x^2 dx = x^3 + C$

  • Example 3: $\int e^x dx = e^x + C$

  • Example 4: $\int \frac{1}{x} dx = \ln|x| + C$

Properties of Antiderivatives

  • Constant Multiple: $\int c f(x) dx = c \int f(x) dx$

  • Sum/Difference: $\int [f(x) \pm g(x)] dx = \int f(x) dx \pm \int g(x) dx$

Antiderivatives as Areas

Area Under a Graph

The area under a velocity-time graph represents the distance traveled. For constant velocity, the area is a rectangle; for variable velocity, it may be a triangle, trapezoid, or more complex region.

  • Example: A vehicle travels at 50 mi/hr for 2 hr. The area under the graph is $2 \times 50 = 100$ mi.

Area under constant velocity graph

  • Example: For $v(x) = 3x$, the area from $x=0$ to $x=3$ is a triangle with area $\frac{1}{2} \times 3 \times 9 = 13.5$ mi.

Area under linear velocity graph (triangle)

  • Example: For $x=3$ to $x=5$, the area is a trapezoid (rectangle plus triangle): $18 + 6 = 24$ mi.

Area under linear velocity graph (trapezoid)

Riemann Sums

Riemann sums approximate the area under a curve by dividing the interval into subintervals and summing the areas of rectangles.

  • General Form: $\sum_{i=1}^n f(x_i) \Delta x$

  • As $n \to \infty$ and $\Delta x \to 0$, the sum approaches the exact area.

Riemann sum rectangles under a curve

Definite Integral

The definite integral gives the exact area under a curve $y = f(x)$ from $x = a$ to $x = b$:

  • $\int_a^b f(x) dx$

  • Represents the limit of Riemann sums as the number of rectangles increases without bound.

Definite integral as exact area under a curve

Area and Definite Integrals

Evaluating Definite Integrals

To find the area under a curve, find an antiderivative $F(x)$ of $f(x)$ and compute $F(b) - F(a)$.

  • Fundamental Theorem of Calculus: $\int_a^b f(x) dx = F(b) - F(a)$, where $F'(x) = f(x)$.

Example

  • Find the area under $y = 3x + 2$ from $x = 0$ to $x = 2$:

  • Antiderivative: $F(x) = \frac{3}{2}x^2 + 2x$

  • Area: $F(2) - F(0) = (6 + 4) - 0 = 10$

Area under a linear function using definite integral

Applications of Definite Integrals

  • Profit Example: The area under $y = 1/x$ from $x = 1$ to $x = 4$ represents total profit as miles increase from 1000 to 4000.

  • Calculation: $\int_1^4 \frac{1}{x} dx = \ln 4 - \ln 1 = \ln 4 \approx 1.3863$

Area under 1/x as profit

  • Net Signed Area: If the function dips below the x-axis, the definite integral gives the net area (positive above, negative below).

Net signed area under a cubic function

  • Business Example: Marginal profit $P'(x) = \sqrt{x} - 6$; total profit for 60 seats is $\int_0^{60} (\sqrt{x} - 6) dx$.

Marginal profit and total profit as area under curve

Properties of Definite Integrals

Additive Property

The definite integral over an interval can be split at any point $c$ between $a$ and $b$:

  • $\int_a^b f(x) dx = \int_a^c f(x) dx + \int_c^b f(x) dx$

Additive property of definite integrals

Area Between Curves

The area between two curves $f(x)$ and $g(x)$ (where $f(x) \geq g(x)$ on $[a, b]$) is:

  • $\int_a^b [f(x) - g(x)] dx$

Area between two curves

Example

  • Find the area between $f(x) = 2x + 1$ and $g(x) = x^2 + 1$ from $x = 0$ to $x = 2$.

Area between a line and a parabola

Average Value of a Function

The average value of a continuous function $f(x)$ over $[a, b]$ is:

  • $y_{av} = \frac{1}{b-a} \int_a^b f(x) dx$

Average value of a function over an interval

Moving Average

The moving average function smooths out fluctuations in data by averaging over a fixed interval $L$:

  • $f_{av}(x) = \frac{1}{L} \int_x^{x+L} f(t) dt$

Moving average of weekly revenue

Integration Techniques: Substitution

Substitution Method

Substitution is used to simplify integrals by changing variables. It is especially useful when the integrand contains a function and its derivative.

  • General Steps:

    1. Let $u = g(x)$, where $g(x)$ is a function inside the integrand.

    2. Compute $du = g'(x) dx$.

    3. Rewrite the integral in terms of $u$ and $du$.

    4. Integrate with respect to $u$.

    5. Substitute back $u = g(x)$.

Common Substitution Formulas

  • $\int u^r du = \frac{u^{r+1}}{r+1} + C$, $r \neq -1$

  • $\int e^u du = e^u + C$

  • $\int \frac{1}{u} du = \ln|u| + C$

Examples

  • Example 1: $\int 3x^2 (x^3 + 1)^{10} dx$ Let $u = x^3 + 1$, $du = 3x^2 dx$ $\int u^{10} du = \frac{u^{11}}{11} + C = \frac{(x^3 + 1)^{11}}{11} + C$

  • Example 2: $\int \frac{2x}{x^2 + 1} dx$ Let $u = x^2 + 1$, $du = 2x dx$ $\int \frac{1}{u} du = \ln|u| + C = \ln|x^2 + 1| + C$

Definite Integrals with Substitution

  • Change the limits of integration to match the new variable $u$.

  • Alternatively, substitute back to $x$ before evaluating at the original limits.

Summary Table: Key Integration Formulas

Rule

Formula

Constant Rule

$\int k dx = kx + C$

Power Rule

$\int x^n dx = \frac{x^{n+1}}{n+1} + C$, $n \neq -1$

Exponential Rule

$\int e^{ax} dx = \frac{1}{a} e^{ax} + C$

Logarithm Rule

$\int \frac{1}{x} dx = \ln|x| + C$

Sum/Difference

$\int [f(x) \pm g(x)] dx = \int f(x) dx \pm \int g(x) dx$

Constant Multiple

$\int c f(x) dx = c \int f(x) dx$

Additional info: These notes cover the core concepts of integration, including antidifferentiation, definite integrals, properties, applications, and the substitution technique, as presented in a standard Calculus college course.

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