IndietroComprehensive Calculus I Study Guide: Step-by-Step Guidance
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Q1. Solve the equation: $\ln x + \ln(x-3) = 0$
Background
Topic: Exponential and Logarithmic Equations
This question tests your understanding of logarithmic properties and how to solve equations involving natural logarithms.
Key Terms and Formulas
Natural logarithm: $\ln x$ is the logarithm base $e$.
Logarithm property: $\ln a + \ln b = \ln(ab)$
To solve $\ln y = 0$, recall that $y = 1$.
Step-by-Step Guidance
Combine the two logarithms using the property $\ln a + \ln b = \ln(ab)$.
Set the resulting logarithm equal to zero: $\ln(x(x-3)) = 0$.
Recall that $\ln y = 0$ implies $y = 1$. Set $x(x-3) = 1$.
Rewrite the equation as a quadratic: $x^2 - 3x - 1 = 0$.
Try solving on your own before revealing the answer!
Final Answer:
The solutions are $x = \frac{3 + \sqrt{13}}{2}$ and $x = \frac{3 - \sqrt{13}}{2}$, but only $x = \frac{3 + \sqrt{13}}{2}$ is valid since $x > 3$ for $\ln(x-3)$ to be defined.
Q2. Solve the equation: $\ln x + \ln(x-3) = \ln 4$
Background
Topic: Exponential and Logarithmic Equations
This question tests your ability to manipulate logarithmic equations and solve for $x$.
Key Terms and Formulas
Logarithm property: $\ln a + \ln b = \ln(ab)$
If $\ln y = \ln k$, then $y = k$.
Step-by-Step Guidance
Combine the left side: $\ln x + \ln(x-3) = \ln(x(x-3))$.
Set $\ln(x(x-3)) = \ln 4$.
Since the logarithms are equal, set their arguments equal: $x(x-3) = 4$.
Rewrite as a quadratic: $x^2 - 3x - 4 = 0$.
Try solving on your own before revealing the answer!
Final Answer:
The solutions are $x = 4$ and $x = -1$. Only $x = 4$ is valid since $x > 3$ for $\ln(x-3)$ to be defined.
Q3. Solve the equation: $7^{2x+1} = 21$
Background
Topic: Exponential Equations
This question tests your ability to solve equations where the variable is in the exponent.
Key Terms and Formulas
Exponential equation: $a^{bx+c} = d$
Take logarithms on both sides to bring down the exponent.
Recall that $21 = 7 \times 3$.
Step-by-Step Guidance
Rewrite $21$ as $7 \times 3$ to see if you can match the base.
Take the natural logarithm (or log base 7) of both sides: $\ln(7^{2x+1}) = \ln 21$.
Use the property $\ln(a^b) = b \ln a$ to bring down the exponent.
Solve for $x$ by isolating it on one side of the equation.
Try solving on your own before revealing the answer!
Final Answer:
$x = \frac{\ln 3}{2 \ln 7}$
We used logarithms to isolate $x$ in the exponent.
Q4. Solve the equation: $3^{5x+2} = 12$
Background
Topic: Exponential Equations
This question tests your ability to solve for $x$ when it appears in the exponent.
Key Terms and Formulas
Exponential equation: $a^{bx+c} = d$
Take logarithms on both sides to bring down the exponent.
Step-by-Step Guidance
Take the natural logarithm (or log base 3) of both sides: $\ln(3^{5x+2}) = \ln 12$.
Use the property $\ln(a^b) = b \ln a$ to bring down the exponent.
Isolate $x$ by moving terms involving $x$ to one side and constants to the other.
Divide both sides by the coefficient of $x$ to solve for $x$.
Try solving on your own before revealing the answer!
Final Answer:
$x = \frac{\ln 12 - 2 \ln 3}{5 \ln 3}$
We used logarithms to solve for $x$ in the exponent.
Q5. Solve the equation: $3\ln x = 5$
Background
Topic: Logarithmic Equations
This question tests your ability to solve for $x$ in a logarithmic equation.
Key Terms and Formulas
Property: $a \ln x = \ln x^a$
To solve $\ln y = k$, use $y = e^k$.
Step-by-Step Guidance
Divide both sides by 3 to isolate $\ln x$.
Exponentiate both sides to solve for $x$.
Try solving on your own before revealing the answer!
Final Answer:
$x = e^{5/3}$
We isolated $\ln x$ and exponentiated both sides to solve for $x$.
Q6. Solve the equation: $e^{2x^2-7x-15} = 1$
Background
Topic: Exponential Equations
This question tests your understanding of the properties of the exponential function and how to solve for $x$ in the exponent.
Key Terms and Formulas
Recall: $e^y = 1$ if and only if $y = 0$.
Step-by-Step Guidance
Set the exponent equal to zero: $2x^2 - 7x - 15 = 0$.
Rewrite as a quadratic equation and prepare to solve for $x$.
Try solving on your own before revealing the answer!
Final Answer:
$x = \frac{7 \pm \sqrt{109}}{4}$
We set the exponent to zero and solved the quadratic equation.
Q7. Find the exact value: $\log_{15} 9 + \log_{15} 25$
Background
Topic: Logarithmic Properties
This question tests your ability to use properties of logarithms to combine and evaluate expressions.
Key Terms and Formulas
Property: $\log_b a + \log_b c = \log_b (ac)$
Step-by-Step Guidance
Combine the two logarithms using the property above.
Evaluate $9 \times 25$ to get the argument of the single logarithm.
Express the result as $\log_{15} (225)$.
Recall that $225 = 15^2$.
Try solving on your own before revealing the answer!
Final Answer:
$\log_{15} 9 + \log_{15} 25 = 2$
Because $\log_{15} (15^2) = 2$.
Q8. Find the exact value: $e^{3\ln 5 + 7\ln 2}$
Background
Topic: Exponential and Logarithmic Properties
This question tests your ability to simplify expressions involving exponents and logarithms.
Key Terms and Formulas
$e^{a \ln b} = b^a$
$e^{A+B} = e^A \cdot e^B$
Step-by-Step Guidance
Rewrite $3\ln 5$ as $\ln 5^3$ and $7\ln 2$ as $\ln 2^7$.
Combine the exponents: $e^{\ln 5^3 + \ln 2^7} = e^{\ln(5^3 \cdot 2^7)}$.
Recall that $e^{\ln a} = a$.
Multiply $5^3$ and $2^7$ to get the final value.
Try solving on your own before revealing the answer!
Final Answer:
$e^{3\ln 5 + 7\ln 2} = 1000 \times 128 = 32000$
We used properties of exponents and logarithms to simplify.
Q9. Find the exact value: $\log_b \frac{\sqrt{x}}{\sqrt[3]{z}}$ when $\log_b x = 2.4$ and $\log_b z = 3.6$
Background
Topic: Logarithmic Properties
This question tests your ability to use properties of logarithms to simplify and evaluate expressions.
Key Terms and Formulas
$\log_b \frac{A}{B} = \log_b A - \log_b B$
$\log_b A^k = k \log_b A$
$\sqrt{x} = x^{1/2}$, $\sqrt[3]{z} = z^{1/3}$
Step-by-Step Guidance
Rewrite $\sqrt{x}$ as $x^{1/2}$ and $\sqrt[3]{z}$ as $z^{1/3}$.
Apply the logarithm properties: $\log_b x^{1/2} = \frac{1}{2} \log_b x$ and $\log_b z^{1/3} = \frac{1}{3} \log_b z$.
Combine using $\log_b \frac{A}{B} = \log_b A - \log_b B$.
Substitute the given values for $\log_b x$ and $\log_b z$.
Try solving on your own before revealing the answer!
Final Answer:
$\log_b \frac{\sqrt{x}}{\sqrt[3]{z}} = \frac{1}{2}(2.4) - \frac{1}{3}(3.6) = 1.2 - 1.2 = 0$
The expression simplifies to zero.