IndietroComprehensive Calculus Practice Exam Guidance
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Q1(a). Calculate the volume of the solid obtained by rotating the region from to about the -axis.
Background
Topic: Volumes of solids of revolution (Calculus II)
This question tests your ability to set up and compute the volume of a solid formed by rotating a region about the -axis, using integration.
Key Terms and Formulas
Solid of revolution
Disk/washer method
Volume formula (about -axis):
Step-by-Step Guidance
Identify the bounds for . Since goes from $0, solve for when and .
Express in terms of : , so the region is bounded by and .
Set up the volume integral using the disk method about the -axis: .
Substitute into the formula: .
Determine the limits and by solving for when and .
Try solving on your own before revealing the answer!
Final Answer:
When , . When , , so .
The volume is .
Evaluating this integral gives .
This result comes from integrating the square of the tangent function over the interval .
Q1(b). Calculate the volume of the solid obtained by rotating the region from to about the -axis.
Background
Topic: Volumes of solids of revolution (washer method)
This question tests your ability to set up and compute the volume of a solid formed by rotating a region about the -axis.
Key Terms and Formulas
Washer method
Volume formula (about -axis): (for shell method), or (for disk/washer method)
Step-by-Step Guidance
Sketch the region: goes from $0, with from $0.
Since rotating about the -axis, consider using the shell method: , where is the height of the shell.
Here, .
Set up the integral: .
Expand and simplify the integrand before integrating.
Try solving on your own before revealing the answer!
Final Answer:
Evaluating gives .
This is the volume of the solid formed by rotating the given region about the -axis.
Q1(c). Calculate the volume of the solid obtained by rotating the region from to about the -axis.
Background
Topic: Volumes of solids of revolution (disk method)
This question tests your ability to set up and compute the volume of a solid formed by rotating a region about the -axis.
Key Terms and Formulas
Disk method
Volume formula (about -axis):
Step-by-Step Guidance
Identify the bounds: goes from $0\frac{\pi}{4}$.
The region is bounded above by and below by .
Set up the volume integral: .
Simplify using trigonometric identities.
Prepare to integrate the resulting expression over .
Try solving on your own before revealing the answer!
Final Answer:
So
Evaluating gives
This is the volume of the solid formed by rotating the region about the -axis.
Q1(d). Calculate the volume of the solid obtained by rotating the region from to about the -axis.
Background
Topic: Volumes of solids of revolution (shell method)
This question tests your ability to set up and compute the volume of a solid formed by rotating a region about the -axis.
Key Terms and Formulas
Shell method
Volume formula (about -axis):
Step-by-Step Guidance
Identify the bounds: goes from $0\sqrt{2}$.
For each , goes from $0y^2y^2$.
Set up the shell method integral: .
Simplify the integrand before integrating.
Prepare to integrate over .
Try solving on your own before revealing the answer!
Final Answer:
This is the volume of the solid formed by rotating the region about the -axis.
Q1(e). Calculate the volume of the solid obtained by rotating the region for to about the -axis.
Background
Topic: Volumes of solids of revolution (disk method)
This question tests your ability to set up and compute the volume of a solid formed by rotating a region about the -axis.
Key Terms and Formulas
Disk method
Volume formula:
Step-by-Step Guidance
Identify the bounds: goes from $0\frac{\pi}{2}$.
The region is bounded above by and below by .
Set up the volume integral: .
Simplify to .
Prepare to integrate over .
Try solving on your own before revealing the answer!
Final Answer:
This is the volume of the solid formed by rotating the region about the -axis.
Q1(f). Calculate the volume of the solid obtained by rotating the region from to about the -axis.
Background
Topic: Volumes of solids of revolution (shell method)
This question tests your ability to set up and compute the volume of a solid formed by rotating a region about the -axis.
Key Terms and Formulas
Shell method
Volume formula:
Step-by-Step Guidance
Identify the bounds: goes from $0.
For each , the height is .
Set up the shell method integral: .
Simplify the integrand: .
Prepare to integrate over .
Try solving on your own before revealing the answer!
Final Answer:
Let , , so .
Substitute and evaluate:
This is the volume of the solid formed by rotating the region about the -axis.
Q2(a). Find the arclength of the curve from to .
Background
Topic: Arc length of a curve (Calculus II)
This question tests your ability to compute the length of a curve using the arc length formula.
Key Terms and Formulas
Arc length formula:
Step-by-Step Guidance
Find for .
Compute and add $1$ to get the expression under the square root.
Set up the arc length integral: .
Simplify the integrand as much as possible.
Prepare to integrate over .
Try solving on your own before revealing the answer!
Final Answer:
So
The arc length is $12$ units.
Q2(b). Find the arclength of the curve from to .
Background
Topic: Arc length of a curve (parametric form)
This question tests your ability to compute the length of a curve given as a function of .
Key Terms and Formulas
Arc length formula:
Step-by-Step Guidance
Find for .
Compute and add $1$ to get the expression under the square root.
Set up the arc length integral: .
Simplify the integrand as much as possible.
Prepare to integrate over .
Try solving on your own before revealing the answer!
Final Answer:
Set up and evaluate numerically or symbolically.
The exact value is .
Q2(c). Find the arclength of the curve from to .
Background
Topic: Arc length of a curve (Calculus II)
This question tests your ability to compute the length of a curve using the arc length formula.
Key Terms and Formulas
Arc length formula:
Step-by-Step Guidance
Find for .
Compute and add $1$ to get the expression under the square root.
Set up the arc length integral: .
Simplify the integrand as much as possible.
Prepare to integrate over .
Try solving on your own before revealing the answer!
Final Answer:
Set up and evaluate .
Q3(a). Find the surface area of the surface of revolution , revolved around the -axis.
Background
Topic: Surface area of revolution (Calculus II)
This question tests your ability to compute the surface area of a solid formed by revolving a curve about the -axis.
Key Terms and Formulas
Surface area formula:
Step-by-Step Guidance
Find for .
Compute and add $1$ to get the expression under the square root.
Set up the surface area integral: .
Simplify the integrand as much as possible.
Prepare to integrate over .
Try solving on your own before revealing the answer!
Final Answer:
This integral gives the surface area of the solid formed by revolving the curve about the -axis.
Q3(b). Find the surface area of the surface of revolution , revolved around the -axis.
Background
Topic: Surface area of revolution (Calculus II)
This question tests your ability to compute the surface area of a solid formed by revolving a curve about the -axis.
Key Terms and Formulas
Surface area formula:
Step-by-Step Guidance
Find for .
Compute and add $1$ to get the expression under the square root.
Set up the surface area integral: .
Simplify the integrand as much as possible.
Prepare to integrate over .
Try solving on your own before revealing the answer!
Final Answer:
This integral gives the surface area of the solid formed by revolving the curve about the -axis.
Q3(c). Find the surface area of the surface of revolution , revolved around the -axis.
Background
Topic: Surface area of revolution (parametric form)
This question tests your ability to compute the surface area of a solid formed by revolving a curve about the -axis, given as a function of .
Key Terms and Formulas
Surface area formula:
Step-by-Step Guidance
Find for .
Compute and add $1$ to get the expression under the square root.
Set up the surface area integral: .
Simplify the integrand as much as possible.
Prepare to integrate over .
Try solving on your own before revealing the answer!
Final Answer:
This integral gives the surface area of the solid formed by revolving the curve about the -axis.