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Ch. 10 - Sequences and Infinite Series
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Non è quello che usi tu?Cambia libro di testo
Tutti i libri di testoBriggs 3rd EditionCh. 10 - Sequences and Infinite SeriesProblema 10.1.59a
Capitolo 10, Problema 10.1.59a

57–60. Heights of bouncing balls A ball is thrown upward to a height of hₒ meters. After each bounce, the ball rebounds to a fraction r of its previous height. Let hₙ be the height after the nth bounce. Consider the following values of hₒ and r.


a. Find the first four terms of the sequence of heights {hₙ}.


h₀ = 30,r = 0.25

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Understand the problem: The ball is initially thrown to a height of \(h_0 = 30\) meters. After each bounce, it reaches a height that is a fraction \(r = 0.25\) of the previous height. We want to find the first four terms of the sequence \(\{h_n\}\), where \(h_n\) is the height after the \(n\)th bounce.
Recall the formula for the height after the \(n\)th bounce: \(h_n = h_0 \times r^n\). This means each term is the initial height multiplied by the rebound fraction raised to the power of the bounce number.
Calculate the first term \(h_0\): This is the initial height before any bounce, so \(h_0 = 30\) meters.
Calculate the second term \(h_1\): Use the formula \(h_1 = 30 \times 0.25^1\) to find the height after the first bounce.
Calculate the third and fourth terms \(h_2\) and \(h_3\): Similarly, use \(h_2 = 30 \times 0.25^2\) and \(h_3 = 30 \times 0.25^3\) to find the heights after the second and third bounces respectively.

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Concetti chiave

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Geometric Sequences

A geometric sequence is a sequence of numbers where each term after the first is found by multiplying the previous term by a constant ratio. In this problem, the heights after each bounce form a geometric sequence with initial term h₀ and common ratio r.
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Geometric Sequences - Recursive Formula

Initial Term and Common Ratio

The initial term (h₀) represents the starting height of the ball, while the common ratio (r) is the fraction of the height the ball reaches after each bounce. These two values define the entire sequence of heights.
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Percorso guidato
05:03
Initial Value Problems

Sequence Notation and Term Calculation

The nth term of a geometric sequence is given by hₙ = h₀ * rⁿ. Using this formula, you can calculate the height after any bounce by raising the ratio to the power of n and multiplying by the initial height.
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Introduction to Sequences
Pratica correlata
Domanda del libro di testo

Explain why or why not

Determine whether the following statements are true and give an explanation or counterexample.

a. If the Limit Comparison Test can be applied successfully to a given series with a certain comparison series, the Comparison Test also works with the same comparison series.

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{Use of Tech} Drug Dosing

A patient takes 75 mg of a medication every 12 hours; 60% of the medication in the blood is eliminated every 12 hours.



a.Let dₙ equal the amount of medication (in mg) in the bloodstream after n doses, where d₁ = 75.

Find a recurrence relation for dₙ.

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27–34. Working with sequences Several terms of a sequence {aₙ}ₙ₌₁∞ are given.

a. Find the next two terms of the sequence.


{1, 3, 9, 27, 81, ......}

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Explain why or why not Determine whether the following statements are true and give an explanation or counterexample.

a. Suppose 0 < aₖ < bₖ. If ∑ (k = 1 to ∞) aₖ converges, then ∑ (k = 1 to ∞) bₖ converges.

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Explain why or why not Determine whether the following statements are true and give an explanation or counterexample.


a. A series that converges must converge absolutely.

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72–75. {Use of Tech} Practical sequences

Consider the following situations that generate a sequence


a.Write out the first five terms of the sequence.


Radioactive decay

A material transmutes 50% of its mass to another element every 10 years due to radioactive decay. Let Mₙ be the mass of the radioactive material at the end of the nᵗʰ decade, where the initial mass of the material is M₀ = 20g.

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