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Ch. 5 - Integration
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Non è quello che usi tu?Cambia libro di testo
Capitolo 5, Problema 5.R.102e

Function defined by an integral Let H (𝓍) = ∫₀ˣ √(4 ― t²) dt, for ― 2 ≤ 𝓍 ≤ 2.
(e) Find the value of s such that H (𝓍) = sH(―𝓍)

Guida verificata passo dopo passo
1
Step 1: Understand the problem. The function H(𝓍) is defined as an integral from 0 to 𝓍 of √(4 - t²) dt. The goal is to find the value of s such that H(𝓍) = sH(-𝓍). This involves symmetry properties of the integral and the function.
Step 2: Analyze the integrand √(4 - t²). This function is even because √(4 - t²) = √(4 - (-t)²). This means the integrand is symmetric about the y-axis.
Step 3: Use the property of definite integrals for even functions. For an even function f(t), ∫₀ˣ f(t) dt is equal to ∫₋ˣ⁰ f(t) dt. This symmetry will help relate H(𝓍) and H(-𝓍).
Step 4: Express H(-𝓍) using the definition of the integral. H(-𝓍) = ∫₀⁻ˣ √(4 - t²) dt. By reversing the limits of integration, this becomes H(-𝓍) = -∫₋ˣ⁰ √(4 - t²) dt.
Step 5: Combine the symmetry property and the reversed integral to find the relationship between H(𝓍) and H(-𝓍). Use this relationship to determine the value of s such that H(𝓍) = sH(-𝓍).

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Definite Integral

A definite integral represents the signed area under a curve defined by a function over a specific interval. In this case, H(𝓍) is defined as the integral of √(4 - t²) from 0 to 𝓍, which geometrically corresponds to the area under the curve of the function from the lower limit to the upper limit.
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Percorso guidato
05:43
Definition of the Definite Integral

Symmetry in Functions

Symmetry in functions refers to the property where a function exhibits the same behavior when its input is negated. For the function H(𝓍), understanding its symmetry can help in finding the relationship between H(𝓍) and H(−𝓍), which is crucial for solving the equation H(𝓍) = sH(−𝓍).
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Percorso guidato
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Properties of Functions

Parameterization

Parameterization involves expressing a function in terms of a variable that can take on a range of values. In this context, the variable s acts as a parameter that scales the relationship between H(𝓍) and H(−𝓍). Finding the appropriate value of s requires analyzing how these two integrals relate to each other.
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Parameterizing Equations Example 4
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