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College Algebra Exam 3 Review – Step-by-Step Study Guidance

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Q1. Find a polynomial function of degree 4 that has real zeros of -3 (multiplicity 2), 7 (multiplicity 1), and 1/3 (multiplicity 1).

Background

Topic: Constructing Polynomial Functions from Zeros

This question tests your ability to build a polynomial function when given its real zeros and their multiplicities.

Key Terms and Formulas:

  • Zero (Root): A value of where the polynomial equals zero.

  • Multiplicity: The number of times a particular zero occurs.

  • General Form: If is a zero of multiplicity , then is a factor.

Step-by-Step Guidance

  1. Write the factors for each zero, using the correct multiplicity. For example, for zero with multiplicity 2, the factor is .

  2. Write the factors for the other zeros: $7(x-7) (multiplicity 1) gives .

  3. Multiply all the factors together to form the general polynomial: , where is a leading coefficient (often set to 1 unless otherwise specified).

  4. To avoid fractions in the polynomial, multiply by 3 to get an equivalent factor with integer coefficients: .

Try solving on your own before revealing the answer!

Final Answer:

This polynomial has degree 4 and the specified zeros with the correct multiplicities.

Q2. Determine the zeros and their multiplicities for the polynomial .

Background

Topic: Identifying Zeros and Multiplicities of a Polynomial

This question asks you to find all real zeros of a given polynomial and state their multiplicities.

Key Terms and Formulas:

  • Zero: A value of that makes .

  • Multiplicity: The exponent on the factor corresponding to each zero.

Step-by-Step Guidance

  1. Set each factor in the polynomial equal to zero to find the zeros.

  2. For , set ; for , set ; for , set .

  3. Identify the multiplicity of each zero by looking at the exponent on each factor.

  4. List each zero with its corresponding multiplicity.

Try solving on your own before revealing the answer!

Final Answer:

  • (multiplicity 1)

  • (multiplicity 2)

  • (multiplicity 3)

Each zero comes from setting a factor equal to zero and the multiplicity is the exponent on that factor.

Q3. Determine a potential polynomial function (with smallest degree possible) for the graph shown below. (0,6)

Background

Topic: Constructing a Polynomial from a Graph

This question tests your ability to deduce a polynomial's equation from its graph, using features like intercepts and turning points.

Key Terms and Formulas:

  • Degree: The highest power of in the polynomial.

  • Y-intercept: The value of .

  • Turning Points: The number of local maxima and minima; a degree polynomial can have up to turning points.

Step-by-Step Guidance

  1. Identify the -intercept from the graph, which is the value when (here, ).

  2. Estimate the number of turning points to determine the minimum degree of the polynomial.

  3. Look for -intercepts (real zeros) and their behavior (touching or crossing the axis) to infer multiplicities.

  4. Write a general form for the polynomial using the zeros and multiplicities, and use the -intercept to solve for the leading coefficient.

Try solving on your own before revealing the answer!

Final Answer:

Without the actual graph, a specific answer can't be given, but the process would yield a polynomial such as where is found using .

Plug in to solve for once the zeros and their multiplicities are determined from the graph.

Q4. Analyze and graph a polynomial function. (a)

Background

Topic: Graphing Polynomial Functions

This question tests your understanding of end behavior, intercepts, and turning points for polynomial functions.

Key Terms and Formulas:

  • End Behavior: Determined by the leading term ().

  • Intercepts: Where the graph crosses the axes.

  • Turning Points: Maximum number is degree minus one.

Step-by-Step Guidance

  1. Identify the degree and leading coefficient to determine end behavior. For , as , .

  2. Find the -intercept by evaluating .

  3. Set to find -intercepts (real zeros).

  4. Determine the maximum number of turning points (degree minus one).

Try solving on your own before revealing the answer!

Final Answer:

End behavior: Both ends down. -intercept: . -intercepts: and (double root). Maximum 3 turning points.

Graph will cross at and touch at .

Q5. Analyze and graph a rational function. (a)

Background

Topic: Graphing Rational Functions

This question tests your ability to analyze rational functions for asymptotes, intercepts, and holes.

Key Terms and Formulas:

  • Vertical Asymptotes: Set denominator equal to zero and solve.

  • Horizontal Asymptotes: Compare degrees of numerator and denominator.

  • Holes: Occur if a factor cancels from numerator and denominator.

  • Intercepts: Set numerator or denominator to zero as appropriate.

Step-by-Step Guidance

  1. Factor numerator and denominator completely.

  2. Find vertical asymptotes by setting the denominator factors equal to zero.

  3. Check for holes by seeing if any factors cancel.

  4. Determine horizontal asymptote by comparing degrees.

  5. Find - and -intercepts by setting numerator and denominator to zero, respectively.

Try solving on your own before revealing the answer!

Final Answer:

Vertical asymptotes at and . No holes. Horizontal asymptote at . -intercepts at and (but $x=-5$ is not in the domain). -intercept at .

Q6. Solve the polynomial inequality algebraically.

Background

Topic: Solving Polynomial Inequalities

This question tests your ability to solve inequalities involving polynomials by finding critical points and testing intervals.

Key Terms and Formulas:

  • Critical Points: Values where the expression equals zero.

  • Sign Chart: Used to test intervals between critical points.

Step-by-Step Guidance

  1. Move all terms to one side: .

  2. Factor the expression completely.

  3. Set each factor equal to zero to find critical points.

  4. Use a sign chart to test the sign of the expression in each interval determined by the critical points.

Try solving on your own before revealing the answer!

Final Answer:

Solution:

These intervals are where the expression is negative, based on the sign chart.

Q7. Solve the rational inequality algebraically:

Background

Topic: Solving Rational Inequalities

This question tests your ability to solve inequalities involving rational expressions by finding critical points and testing intervals.

Key Terms and Formulas:

  • Critical Points: Values where the numerator or denominator is zero.

  • Sign Chart: Used to test intervals between critical points.

Step-by-Step Guidance

  1. Subtract 1 from both sides to get a single rational expression: .

  2. Combine into a single fraction and simplify the numerator.

  3. Factor the numerator and denominator if possible.

  4. Find critical points by setting the numerator and denominator equal to zero.

  5. Use a sign chart to test the sign of the expression in each interval.

Try solving on your own before revealing the answer!

Final Answer:

Solution:

These intervals are where the rational expression is greater than or equal to 0, excluding where the denominator is zero.

Q8. Solve this system using the method of elimination:

Background

Topic: Solving Systems of Linear Equations (Elimination Method)

This question tests your ability to solve a system of equations by eliminating one variable.

Key Terms and Formulas:

  • Elimination Method: Multiply equations as needed so that adding or subtracting them eliminates one variable.

Step-by-Step Guidance

  1. Multiply one or both equations so that the coefficients of or are opposites.

  2. Add or subtract the equations to eliminate one variable.

  3. Solve for the remaining variable.

  4. Substitute back into one of the original equations to solve for the other variable.

Try solving on your own before revealing the answer!

Final Answer:

,

Substituting back confirms the solution satisfies both equations.

Q9. Solve this system using the method of substitution:

Background

Topic: Solving Systems of Linear Equations (Substitution Method)

This question tests your ability to solve a system by expressing one variable in terms of the other and substituting.

Key Terms and Formulas:

  • Substitution Method: Solve one equation for one variable, then substitute into the other equation.

Step-by-Step Guidance

  1. Solve the first equation for or .

  2. Substitute this expression into the second equation.

  3. Solve for the remaining variable.

  4. Substitute back to find the other variable.

Try solving on your own before revealing the answer!

Final Answer:

,

Both values satisfy the original system.

Q10. (a) Let and . Determine , its domain, and simplify the result.

Background

Topic: Composition of Functions

This question tests your ability to compose two functions and determine the domain of the resulting function.

Key Terms and Formulas:

  • Composition:

  • Domain: Set of values for which the composition is defined.

Step-by-Step Guidance

  1. Substitute into to get .

  2. Simplify the resulting expression.

  3. Determine the domain by finding values of that do not make any denominator zero.

Try solving on your own before revealing the answer!

Final Answer:

Domain:

We substitute into and simplify, then exclude where is undefined.

Q10. (b) Let and . Determine , its domain, and simplify the result.

Background

Topic: Composition of Functions with Radicals

This question tests your ability to compose functions involving square roots and polynomials, and to find the domain.

Key Terms and Formulas:

  • Composition:

  • Domain: Set of values for which the composition is defined (here, ).

Step-by-Step Guidance

  1. Substitute into to get .

  2. Simplify the resulting expression.

  3. Determine the domain by setting .

Try solving on your own before revealing the answer!

Final Answer:

Domain:

We substitute and simplify, and the domain is determined by the radicand being non-negative.

Q11. The surface area, (in ), of a spherical balloon with radius (in ) is given by . A helium tank can fill the balloon so that its radius is given by , , where is the number of seconds since the start of filling the balloon. Find the surface area of the balloon as a function of time.

Background

Topic: Applications of Function Composition

This question tests your ability to compose functions in a real-world context.

Key Terms and Formulas:

  • Surface Area of a Sphere:

  • Composition:

Step-by-Step Guidance

  1. Substitute into to get .

  2. Simplify the resulting expression to write as a function of .

Try solving on your own before revealing the answer!

Final Answer:

The surface area as a function of time is for .

Q12. The graph of the function is given below. Determine the graph of . (Points: (0,1), (1,3))

Background

Topic: Graphs of Inverse Functions

This question tests your understanding of how to graph the inverse of a function using its original graph.

Key Terms and Formulas:

  • Inverse Function: reverses the roles of and in .

  • Graphical Relationship: The graph of is the reflection of across the line .

Step-by-Step Guidance

  1. Identify key points on the graph of , such as and .

  2. For each point on , plot the point on .

  3. Reflect the entire graph of over the line to obtain .

Try solving on your own before revealing the answer!

Final Answer:

The graph of will have points and , and is the reflection of over the line .

Q13. The function is one-to-one. Find its inverse function, .

Background

Topic: Finding Inverse Functions Algebraically

This question tests your ability to find the inverse of a rational function.

Key Terms and Formulas:

  • Inverse Function: Swap and and solve for .

Step-by-Step Guidance

  1. Replace with and write .

  2. Swap and to get .

  3. Solve for in terms of by multiplying both sides by and isolating .

  4. Express as the final formula.

Try solving on your own before revealing the answer!

Final Answer:

This is found by solving for .

Q14. Demonstrate that and are inverse functions.

Background

Topic: Verifying Inverse Functions

This question tests your ability to verify that two functions are inverses by showing and .

Key Terms and Formulas:

  • Inverse Functions: and for all in the domain.

Step-by-Step Guidance

  1. Compute by substituting into and simplify.

  2. Compute by substituting into and simplify.

  3. Show that both compositions simplify to .

Try solving on your own before revealing the answer!

Final Answer:

Both and , so and are inverses.

This is shown by direct substitution and simplification.

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