IndietroCollege Algebra Practice Test – Step-by-Step Guidance
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Q1. The perimeter of a rectangle is 560 meters. The length is 20 meters less than twice the width. What are the length and width?
a) Write an equation using the variable “x”.
b) Solve the equation.
c) State the answer.
d) Check your answer.
Background
Topic: Linear Equations and Geometry
This question tests your ability to translate a word problem into an algebraic equation, solve for unknowns, and interpret the solution in the context of geometry (perimeter of a rectangle).
Key Terms and Formulas
Perimeter of a rectangle:
Let represent the width. Then, length (since length is 20 meters less than twice the width).
Step-by-Step Guidance
Let be the width of the rectangle. Express the length in terms of $x$ using the information given: .
Write the perimeter formula for a rectangle: .
Substitute the given perimeter ($560LW.
Simplify the equation and combine like terms to form a linear equation in .
Set up the equation so you can solve for in the next step.
Try solving on your own before revealing the answer!
Final Answer:
a) The equation is .
b) Solving: .
c) Width = 100 meters, Length = meters.
d) Check: meters. The answer checks out!
Q2. A projectile is launched straight from the ground level with an initial velocity of 96 ft/sec. Its height in feet, , after seconds is given by: .
a) At what time(s) will it reach a height of 80 ft?
b) After how many seconds will it return to the ground?
Background
Topic: Quadratic Equations and Applications
This question tests your ability to solve quadratic equations in the context of projectile motion, using algebraic methods to find when the projectile reaches a certain height or returns to the ground.
Key Terms and Formulas
Quadratic equation:
Projectile motion formula:
Quadratic formula:
Step-by-Step Guidance
For part (a), set and substitute into the equation: .
Rearrange the equation to standard quadratic form: .
Multiply both sides by to make the leading coefficient positive: .
Identify , , for the quadratic formula.
Set up the quadratic formula for but do not compute the discriminant or final values yet.
For part (b), set (when the projectile returns to the ground): and factor or use the quadratic formula to set up the solution.
Try solving on your own before revealing the answer!
Final Answer:
a)
Calculate:
So, seconds and second.
b) For :
So, (launch) and seconds (returns to ground).
Q3. Dr. Tydings has found that, over the years, 95% of the babies he has delivered weighed pounds, where . What range of weights corresponds to this inequality?
Background
Topic: Absolute Value Inequalities
This question tests your understanding of how to interpret and solve absolute value inequalities, and how to express the solution as an interval.
Key Terms and Formulas
Absolute value inequality: means
Step-by-Step Guidance
Start with the given inequality: .
Recall that is equivalent to .
Apply this property to the given values: .
Set up the range for but do not compute the final interval yet.
Try solving on your own before revealing the answer!
Final Answer:
The range is .
This means 95% of the babies weighed between 6.7 and 9.7 pounds.
Q4. Solve this equation using 2 methods: factoring, completing the square, or using the quadratic equation:
Background
Topic: Solving Quadratic Equations
This question tests your ability to solve quadratic equations using multiple methods: factoring, completing the square, and the quadratic formula.
Key Terms and Formulas
Standard form:
Factoring: Expressing the quadratic as
Completing the square: ...
Quadratic formula:
Step-by-Step Guidance
First, rewrite the equation in standard form: .
Method 1 (Factoring): Try to factor into two binomials.
Set each factor equal to zero to find the possible solutions for .
Method 2 (Quadratic Formula): Identify , , and set up the quadratic formula for .
Write the formula with the values substituted, but do not compute the discriminant or final values yet.
Try solving on your own before revealing the answer!
Final Answer:
Factoring: so or .
Quadratic formula: so or .
Both methods give the same solutions: and .